HDU 4438(Hunters)

题目链接地址：http://acm.hdu.edu.cn/showproblem.php?pid=4438

2012天津赛区现场赛H题

/*简单数学题
只要稍微懂点概率论的知识就能做出来
当Alice首选tiger时，期望为：mp1 = q*(p*x + p*y) + (1-q)*x;
当Alice首选wolf是，期望为：mp2 = q*y + (1-q)*(p*x + p*y);
*/

#include<iostream>
using namespace std;
int t;
double x,y,p,q;
int main()
{
    //freopen("4438.txt","r",stdin);
    scanf("%d",&t);
    while(t--)
    {
        double mp1,mp2;
        scanf("%lf%lf%lf%lf",&x,&y,&p,&q);
        mp1 = q*(p*x + p*y) + (1-q)*x;
        mp2 = q*y + (1-q)*(p*x + p*y);
        if(mp1 > mp2)  printf("tiger %.4lf\n",mp1);
        else printf("wolf %.4lf\n",mp2);
    }
    return 0;
}