第四次上机

1.编写一个简单程序,要求数组长度为5,静态赋值10,20,30,40,50,在控制台输出该数组的值。

package come.itheima01;
import java.util.Scanner;
public class Sz {
    public static void main(String[] args) {
        
        int[] arr = new int[] { 10, 20, 30, 40, 50 };
        for (int i = 0; i < arr.length; i++) {
        System.out.print(arr[i] + " ");
        }
        }
        }

2.编写一个简单程序,要求数组长度为5,动态赋值10,20,30,40,50,在控制台输出该数组的值。

package come.itheima01;
import java.util.Scanner;
public class Sz {
    public static void main(String[] args) {
        
        int[] a = new int[6];
        for (int i = 1; i < a.length; i++) {
        a[i]+=a[i-1]+10;
        System.out.print(a[i] + " ");
        }
        }
        }

3.编写一个简单程序,定义整型数组,里面的元素是{23,45,22,33,56},求数组元素的和、平均值


package come.itheima01;
import java.util.Scanner;
public class Sz {
public static void main(String[] args) {

int[] a = new int[]{23,45,22,33,56};
int sum=0,pj=0;
for (int i = 0; i < a.length; i++) {
sum+=a[i];
}
pj=sum/5;
System.out.println(sum + " " + pj);
}
}

 

4.在一个有8个整数(18,25,7,36,13,2,89,63)的数组中找出其中最大的数及其下标。

package come.itheima01;
import java.util.Scanner;
public class Sz {
    public static void main(String[] args) {
        
        int[] a = new int[] { 18, 25, 7, 36, 13, 2, 89, 63 };
        int max = a[0];
        for (int i = 0; i < a.length; i++) {
        if (max < a[i]) {
        max = a[i];
        }
        }
        System.out.println("最大值是:" + max);
        int count = 0;
        for (int i = 0; i < a.length; i++) {
        if (a[i] == max) {
        System.out.println("下标值是:" + count);
        }
        count++;
        }
        }
        }

 5、将一个数组中的元素逆序存放(知识点:数组遍历。数组元素访问)

package come.itheima01;

public class Sz {
    public static void main(String[] args) {
          
                  int[] grade = {87,88,89,98,78};
          
                  int m;
                  for(int i = 0; i < 2; i++){
          
                     m = grade[i];
                     grade[i] = grade[5-i-1];
                     grade[5-i-1] = m;
         
                 }
                 for(int j =0; j < 5; j++){
                     System.out.println(grade[j]);
                 }
         
             }
         
         }

 

posted @ 2020-04-09 11:06  Silent222  阅读(...)  评论(...编辑  收藏