1017A Mathematical Curiosity C

题目：http://acm.hdu.edu.cn/showproblem.php?pid=1017

#include <stdio.h>

int main(){
    int N,n,m,a,b,count=0,Case;
    scanf("%d", &N);
    while (N--)
    {
        int Case = 1;
        while (scanf("%d %d",&n,&m)!=EOF)
        {
            if (n == 0 && m == 0)
            {
                break;
            }
            if (0 > n || n > 100)
            {
                break;
            }
            for ( a = 1; a < n-1; a++)
            {
                for ( b = a+1; b < n; b++)
                {
                    if ((a*a + b*b + m)%(a * b)== 0)
                    {
                        count++;
                    }
                }
            }
            printf("Case %d: %d\n", Case++, count);
            count = 0;

        }
        if (N > 0)
        printf("\n");
    }
}

输出的显示：

2
10 1
Case 1: 2
20 3
Case 2: 4
30 4
Case 3: 5
0 0

10 1
Case 1: 2
20 3
Case 2: 4
30 4
Case 3: 5
0 0

注：题目感觉有点坑，上面明明有一个空行，结果按照样例输入结果就是不多