实验2
task1源代码
1 #include <stdio.h> 2 #include <stdlib.h> 3 #include <time.h> 4 5 #define N 5 6 7 int main() { 8 int number; 9 int i; 10 11 srand(time(0)); // 以当前系统时间作为随机种子 12 for (i = 0; i < N; ++i) { 13 number = rand() % 100 + 1; 14 printf("20490042%04d\n", number); 15 } 16 17 return 0; 18 }
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问题1:随机生成专业学员编号
问题2:line13是将1-100随机数赋值给numble
问题3:在42后再留四位数空间且补位为0
问题4:使生成数随机,弃掉后多次运行生成结果相同
task2源代码
1 #include <stdio.h> 2 int main() { 3 int choice, quantity; 4 float total_price = 0, amount_paid, change; 5 while (1) { 6 printf("\n自动饮料售卖机菜单:\n"); 7 printf("1. 可乐 - 3 元/瓶\n"); 8 printf("2. 雪碧 - 3 元/瓶\n"); 9 printf("3. 橙汁 - 5 元/瓶\n"); 10 printf("4. 矿泉水 - 2 元/瓶\n"); 11 printf("0. 退出购买流程\n"); 12 printf("请输入饮料编号: "); 13 scanf_s("%d", &choice); 14 if (choice == 0) 15 break; 16 if (choice < 1 || choice > 4) { 17 printf("无效的饮料编号,请重新输入。\n"); 18 continue; 19 } 20 printf("请输入购买的数量: "); 21 scanf_s("%d", &quantity); 22 if (quantity < 0) { 23 printf("购买数量不能为负数,请重新输入。\n"); 24 continue; 25 } 26 if (choice == 1 || choice == 2) 27 total_price += 3 * quantity; 28 else if (choice == 3) 29 total_price += 5 * quantity; 30 else 31 total_price += 2 * quantity; 32 printf("请投入金额: "); 33 scanf_s("%f", &amount_paid); 34 change = amount_paid - total_price; 35 printf("本次购买总价: %.2f 元\n", total_price); 36 printf("找零: %.2f 元\n", change); 37 total_price = 0; 38 } 39 printf("感谢您的购买,欢迎下次光临!\n"); 40 return 0; 41 }
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问题1:去掉后第二次运行会将第一次的总价加在一起导致错误
问题2:跳过本次循环的剩下的所有语句,直接进入下一次循环
task3源代码
1 #include<stdio.h> 2 int main() 3 { 4 char symble; 5 while (scanf_s("%c", &symble) != EOF) { 6 if (symble == '\n') { 7 continue; 8 } 9 switch (symble) 10 { 11 case'r': 12 printf("stop\n"); 13 break; 14 case'g': 15 printf("go go go\n"); 16 break; 17 case'y': 18 printf("wait a minute\n"); 19 break; 20 default: 21 printf("something must be wrong\n"); 22 break; 23 } 24 } 25 return 0; 26 }
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task4源代码
1 #include<stdio.h> 2 #include<math.h> 3 int main() 4 { 5 double sum = 0.0, max = 0.0, min = 20000.0, n; 6 printf("一天内的若干笔开销:\n"); 7 8 while (1) { 9 scanf_s("%lf", &n); 10 if (n == -1) { 11 break; 12 } 13 if (n <= 0 || n >= 20000) { 14 printf("输入无效,输入0<n<20000的数值\n"); 15 continue; 16 } 17 sum += n; 18 if (n > max) { 19 max = n; 20 } 21 if (n < min) { 22 min = n; 23 } 24 } 25 printf("最高一笔开销:%.1f\n",max); 26 printf("最低一笔开销:%.1f\n",min); 27 printf("一天总开销:%.1f\n",sum); 28 return 0; 29 }
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task5源代码
1 #include<stdio.h> 2 #include<stdlib.h> 3 #include<math.h> 4 int main() { 5 int a, b, c; 6 while (scanf_s("%d %d %d", &a, &b, &c) != EOF) { 7 if (a + b <= c || a + c <= b || b + c <= a) { 8 printf("不能构成三角形\n"); 9 } 10 else if (a == b && b == c) { 11 printf("等边三角形\n"); 12 } 13 else if (a == b || a == c || b == c) { 14 printf("等腰三角形\n"); 15 } 16 else if (a*a + b * b == c * c || a * a + c * c == b * b || b * b + c * c == a * a) { 17 printf("直角三角形\n"); 18 } 19 else { 20 printf("普通三角形\n"); 21 } 22 } 23 return 0; 24 }
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task6源代码
1 #include<stdio.h> 2 #include<stdlib.h> 3 #include<time.h> 4 int main() { 5 int lucky_day; 6 int chance=3; 7 int a; 8 srand((unsigned int)time(0)); 9 lucky_day = rand() % 30 + 1; 10 printf("猜猜2026年4月哪一天是你的lucky day\n"); 11 while (chance > 0) { 12 if (chance == 3) { 13 printf("开始喽,你有三次机会,猜吧(1-30):"); 14 } 15 else { 16 printf("再猜(1 - 30):"); 17 } 18 scanf_s("%d", &a); 19 chance--; 20 if (a == lucky_day) { 21 printf("哇,猜中了:)\n"); 22 break; 23 } 24 25 else if (a > lucky_day) { 26 printf("你猜的日期晚了,你的lucky day在前面哦\n"); 27 28 } 29 else { 30 printf("你猜的日期早了,你的lucky day还没到呢\n"); 31 } 32 } 33 printf("次数用光了。4月你的lucky day是%d号\n,",lucky_day); 34 35 36 37 return 0; 38 }
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