7.Reverse Integer

class Solution {
public:
    int reverseInteger(int n) {
        long long res = 0;
        while (n != 0) {
            res = 10 * res + n % 10;
            n /= 10;
        }
        return (res < INT_MIN || res > INT_MAX) ? 0 : res;
    }
};
posted @ 2019-04-08 17:07  JohnRed  阅读(58)  评论(0编辑  收藏  举报