数据为:id flow sex name22 0 1 128 1 2 328 2 1 3需要用SQL取出id相同的条件下flow最大的记录,还要有其他ID的记录。需要的结果为:id flow sex name22 0 1 128 2 1 3
答案:
select a.* from tt ainner join(select id,max(flow) as ma from tt group by id) bon a.id=b.id and a.flow=b.ma