Python 第二周作业

凯撒密码B

s = input()
t = ""
for c in s:
    if 'a' <= c <= 'z': #str是可以直接比较的
        t += chr( ord('a') + ((ord(c)-ord('a')) + 3 )%26 )
    elif 'A'<=c<='Z':
        t += chr( ord('A') + ((ord(c)-ord('A')) + 3 )%26 )
    else:
        t += c
print(t)

 

括号配对检测A

Str=input("")
Left_bracket=0
Left_bracket_Z=0
Right_bracket_Z=0
for i in Str:
    if i== '(':
        Left_bracket+=1
    elif i== ')':
        if Left_bracket>0:
            Left_bracket-=1
        else:
            print("配对不成功")
            break
    elif i=='[':
        Left_bracket_Z+=1
    elif i==']':
        Right_bracket_Z+=1
else:
    if Left_bracket!=0:
        print("配对不成功")
    elif Left_bracket_Z!=Right_bracket_Z:
        print("配对不成功")
    else:
        print("配对成功")

 

天天向上的力量B

NN=eval(input(""))
Working=pow((1.0+0.001*NN),364)
Pig=pow((1.0-0.001*NN),364)
BB=int(Working//Pig)
print("{:.2f}, {:.2f}, {}".format(Working,Pig,BB))

 

同符号数学运算

n = eval(input())
N = abs(n)
a = N + 10
b = N - 10
c = N * 10
if n < 0:
    a = -abs(a)
    b = -abs(b)
    c = -abs(c)
else:
    a = abs(a)
    b = abs(b)
    c = abs(c)
print(N, a , b, c, end = "")

 

快乐的数字

def happy(n):
        try:
                if n==1:
                        print('True')
                else:
                        new = str(n)
                        sum = 0
                        for c in new:
                                sum += int(c)**2
                        return happy(sum)
        except Exception as e:
                print('False')
               # print(e)

n = eval(input())
happy(n)

 

字符串反码A

while True:
    try:
        string=input()
        if string!="!":
            res=""
            for i in string:
                if i.isupper():
                    res+=chr(ord("Z")-(ord(i)-ord("A")))
                elif i.islower():
                    res += chr(ord("z") - (ord(i) - ord("a")))
                else:
                    res+=i
            print(res)
    except:
        break

 

计算矩形面积

a = float(input())
b = float(input())
square = a*b
print(format(square,'.2f'))

 

格式化输出

num = float(input())
print("{:.3f}".format(num))

字符串逆序输出

str1 = input()
print(str1[::-1])

 

照猫画虎求阶乘

a = int(input())
b = 1
for i in range(1, a+1):
    b = b*i
print("%d" % float(b))