图论09
47. 参加科学大会(第六期模拟笔试)
dijkstra(堆优化版)精讲
#include <iostream>
#include <vector>
#include <climits>
#include <queue>
#include <list>
using namespace std;
class mycomparison {
public:
bool operator()(const pair<int, int>& lhs, const pair<int, int>& rhs) {
return lhs.second > rhs.second;
}
};
struct Edges {
int to;
int val;
Edges(int x, int y): to(x), val(y){}
};
int main() {
int n, m;
cin >> n >> m;
int s, e, v;
vector<list<Edges>> grid(n + 1);
for (int i = 0; i < m; i++) {
cin >> s >> e >> v;
grid[s].push_back(Edges(e, v));
}
priority_queue<pair<int, int>, vector<pair<int, int>>, mycomparison> pq;
int start = 1, end = n;
vector<int> visited(n + 1, 0);
vector<int> minDist(n + 1, INT_MAX);
minDist[start] = 0;
pq.push(pair<int, int>(start, 0));
while (!pq.empty()) {
// 1. 第一步,选源点到哪个节点近且该节点未被访问过 (通过优先级队列来实现)
// <节点, 源点到该节点的距离>
pair<int, int> cur = pq.top(); pq.pop();
if (visited[cur.first]) continue;
// 2. 第二步,该最近节点被标记访问过
visited[cur.first] = true;
// 3. 第三步,更新非访问节点到源点的距离(即更新minDist数组)
for (Edges edge : grid[cur.first]) { // 遍历 cur指向的节点,cur指向的节点为 edge
// cur指向的节点edge.to,这条边的权值为 edge.val
if (!visited[edge.to] && minDist[cur.first] + edge.val < minDist[edge.to]) { // 更新minDist
minDist[edge.to] = minDist[cur.first] + edge.val;
pq.push(pair<int, int>(edge.to, minDist[edge.to]));
}
}
}
if (minDist[end] == INT_MAX) cout << -1;
else {
cout << minDist[end];
}
return 0;
}
94. 城市间货物运输 I
#include <iostream>
#include <vector>
#include <climits>
using namespace std;
int main() {
int n, m;
cin >> n >> m;
int s, t, v;
vector<vector<int>> grid;
vector<int> minDist(n + 1, INT_MAX);
for (int i = 0; i < m; i++) {
cin >> s >> t >> v;
grid.push_back({s, t, v});
}
minDist[1] = 0;
for (int i = 0; i < n - 1; i++) {
for (auto &edge: grid) {
int from = edge[0], to = edge[1], value = edge[2];
if (minDist[from] != INT_MAX && minDist[to] > minDist[from] + value) {
minDist[to] = minDist[from] + value;
}
}
}
if (minDist[n] == INT_MAX) cout << "unconnected";
else cout << minDist[n];
return 0;
}

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