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Request.InputStream
将数据作为XML数据发送,例如:
public
void
PostXml(
string
url,
string
xml)
{
byte
[] bytes
=
Encoding.UTF8.GetBytes(xml);
HttpWebRequest request
=
(HttpWebRequest) WebRequest.Create(url);
request.Method
=
"
POST
"
;
request.ContentLength
=
bytes.Length;
request.ContentType
=
"
text/xml
"
;
using
(Stream requestStream
=
request.GetRequestStream())
{
requestStream.Write(bytes,
0
, bytes.Length);
}
HttpWebResponse response
=
(HttpWebResponse) request.GetResponse();
if
(response.StatusCode
!=
HttpStatusCode.OK)
{
string
message
=
String.Format(
"
POST failed. Received HTTP {0}
"
,
response.StatusCode);
throw
new
ApplicationException(message);
}
}
接收端通过Request.InputStream读取:
byte
[] byts
=
new
byte
[Request.InputStream.Length];
Request.InputStream.Read(byts,
0
,byts.Length);
string
req
=
System.Text.Encoding.Default.GetString(byts);
req
=
Server.UrlDecode(req);
对于完整的XML数据,可以:
xmlDoc
=
new
XmlDocument();
xmlDoc.load(Request.InputStream);
posted @
2008-12-25 22:40
s80895304
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