高精度加法

/*样例输入：2 4
样例输出：6*/

#include <stdio.h>
#include <string.h>

int main()
{
    char s[210];
    int a[100], b[100], c[110];//此处数组数可进行各种更改以更改精度（后面也要依次更改）
    int len=0, i, flag = 0, m=0,n=0,tot1=0,tot2=0,temp=0,tmp=0;
    while (gets_s(s))
    {   //数组清零
        memset(a, 0, sizeof(a));
        memset(b, 0, sizeof(b));
        memset(c, 0, sizeof(c));

        len = strlen(s);
        if (len != 0)
        {
            for (i = 0;i < len;i++)
            {
                if (s[i] == ' ') { flag = 1;continue; }
                if (flag == 0) { a[i] = s[i] - '0';tot1 += 1; }
                if (flag == 1) { b[tot2] = s[i] - '0'; tot2 += 1; } //因为0的ASCII码是48，要减去
            }

            for (i = 0;i < tot1 / 2; i++)
            {
                //交换对应位上的数
                temp = a[i];
                a[i] = a[tot1 - i - 1];
                a[tot1 - i - 1] = temp;
            }
            for (i = 0;i < tot2 / 2; i++)
            {
                temp = b[i];
                b[i] = b[tot2 - i - 1];
                b[tot2 - i - 1] = temp;
            }

            if (tot1 > tot2)m = tot1;
            else m = tot2;
            for (i = 0;i <= m;i++)
            {
                c[i] += a[i] + b[i];
                if (c[i] > 9) { c[i] -= 10;c[i + 1] += 1; }
            }
            for (i = 99;i > 0;i--)
                if (c[i] != 0) { n = i;break; }

            for (i = n;i >= 0;i--)
                printf("%d", c[i]);
        
        printf("\n");}
        memset(s, 0, sizeof(s));
        flag = 0; m = 0;n = 0; tot1 = 0;tot2 = 0;temp = 0; tmp = 0;
    }
    return 0;
}