Matrix bases

$f: R^{m*n} \rightarrow R$, $A \epsilon R^{m*n}$

$\nabla_Af(A) \epsilon R^{m*n} = [\frac{\partial f(A)}{\partial A_{ij}}]$

 

$\nabla_x b^Tx = b$

posted @ 2012-10-01 16:21  sidereal  Views(99)  Comments(0)    收藏  举报