/**
 * Definition for an interval.
 * public class Interval {
 *     int start;
 *     int end;
 *     Interval() { start = 0; end = 0; }
 *     Interval(int s, int e) { start = s; end = e; }
 * }
 */
class Solution {
    public List<Interval> merge(List<Interval> intervals) {
        List<Interval> result = new ArrayList<>();
        if (intervals == null || intervals.size() < 2) {
            return intervals;
        }
        Collections.sort(intervals, new Comparator<Interval>(){
            @Override
            public int compare(Interval i1, Interval i2) {
                return i1.start - i2.start;
            }
        });
        Interval current = intervals.get(0);
        for (int i = 1; i < intervals.size(); i++) {
            if (current.end >= intervals.get(i).start) {
                current.end = Math.max(current.end, intervals.get(i).end);
            } else {
                result.add(current);
                current = intervals.get(i);
            }
        }
        result.add(current);
        return result;
    }
}

 

 

1. Has to be sorted if originally not sorted.

2. When merge end point, it could be totally covered instead of intersect.

posted on 2017-08-21 13:33  keepshuatishuati  阅读(93)  评论(0)    收藏  举报