每日一题--Python打印金字塔

def day1(num):
    s = 'abcdefghijklmnopqrstuvwxyz' * (num // 26 + 1)
    for i in range(1, num + 1):
        print('{0:^{1}}'.format(s[:i] + s[:i -1][::-1], num * 2 -1))


day1(28)

 

posted @ 2020-07-16 11:03  十一的杂文录  阅读(301)  评论(0编辑  收藏  举报