函数式编程总结

a = ["shi", "xiao", "gu"]


def map_func(item: str) -> str:
    """
    产生新集合
    :param item:
    :return:
    """
    item = "da" if item == "xiao" else item
    return item


# map函数
output_res = map(map_func, a)
print(list(output_res))

b = [10, 6, 1, 3, 0, 89]


def filter_func(item: int) -> int:
    """
    筛选子集
    :param item:
    :return:
    """
    if item > 3:
        return item


# filter函数
filtered = filter(filter_func, b)
print(list(filtered))

from functools import reduce

# reduce函数,产生一个结果
sum_ = reduce(lambda x, y: x + y, [3, 6, 1])
print(sum_)

 上面这一部分的手法在重构中称之为：以管道取代循环