Java_数据交换_fastJSON_01_用法入门
一、用法
1.序列化—将Object转为Json对象
Object data=JSON.toJSON( MyObject );
注:本文的Object可以是Map、List、javaBean等
需求:请拼接如下json
{ "openid": [ "o1Pj9jmZvwSyyyyyyBa4aULW2mA", "o1Pj9jmZvxxxxxxxxxULW2mA" ], "username": [ "afdvvf", "abcd" ] }
代码:
Map<String,List<String>> postDataMap= new HashMap<String,List<String>>(); postDataMap.put("openid", openIdList); postDataMap.put("username", userNameList); Object data=JSON.toJSON(postDataMap); system.out.println(data.toString());
2.序列化—将Object转为Json字符串
String data=JSON.toJSONString(MyObject);
需求:请拼接如下字符串:
{}
代码:
Object ob=new Object(); String data=JSON.toJSONString(ob); System.out.println(data);
3.反序列化—将json字符串转为JSONObject
JSONObject jsonObject=JSON.parseObject(str);
Data data = JSON.parseObject(str, Data.class);
需求:将以下Json字符串转为JSONObject
{ "openid": [ "o1Pj9jmZvwSyyyyyyBa4aULW2mA", "o1Pj9jmZvxxxxxxxxxULW2mA" ], "username": [ "afdvvf", "abcd" ] }
代码:
String str="{ " +
" \"openid\": [ " +
" \"o1Pj9jmZvwSyyyyyyBa4aULW2mA\", " +
" \"o1Pj9jmZvxxxxxxxxxULW2mA\" " +
" ], " +
" \"username\": [ " +
" \"afdvvf\", " +
" \"abcd\" " +
" ] " +
" }";
JSONObject jsonObject=JSON.parseObject(str);
System.out.println(jsonObject.toJSONString());
4.通过JSONObject构造json字符串
JSONObject jsonObject=new JSONObject(); jsonObject.put(key, value);
需求:请构造如下json字符串
{ "money": 123, "s_pappid": "djwhei124" }
代码:
JSONObject jsonObject=new JSONObject(); jsonObject.put("s_pappid", "djwhei124"); jsonObject.put("money", 123); System.out.println(jsonObject.toJSONString());
二、参考资料

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