TopCoder SRM596 DIV2 1000: SparseFactorialDiv2
摘要:题意:For an integer n, let F(n) = (n - 0^2) * (n - 1^2) * (n - 2^2) * (n - 3^2) * ... * (n - k^2), where k is the largest integer such that n - k^2 > 0. You are given three long longs lo, hi and divisor. It is guaranteed that divisor will be a prime number. Compute and return the number of integers
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posted @ 2013-11-03 15:52
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