#查找列表中元素，移除每个元素的空格，并查找以 a或A开头 并且以 c 结尾的所有元素

#!/usr/bin/env python
#查找列表中元素，移除每个元素的空格，并查找以 a或A开头 并且以 c 结尾的所有元素。
#    li = ["alec", " aric", "Alex", "Tony", "rain"]
#    tu = ("alec", " aric", "Alex", "Tony", "rain") 
#    dic = {'k1': "alex", 'k2': ' aric',  "k3": "Alex  ", "k4": "Tony"}

li = ["   alex ","aric","Alex","Tony","rain"]
tu = ("alex   ","aric ","Alex ","  Tony"," rain")
dic = {'k1':"alex",'k2':" aric   ",'k3':"Alex",'k4':"Tony"}
for i,j in enumerate(li,0) :
    j = j.strip()
    li[i] = j
    if j.endswith('c') and (j.startswith('a') or j.startswith('A')):
        print(j)
print(li)
print("-------------------")


for j in tu :
    print(j)
    j = j.strip()
    print(j)
    if j.endswith('c') and (j.startswith('a') or j.startswith('A')):
        print(j)
print(tu)
print("-------------------")


for i,j in enumerate(dic,0) :
    print(j)
    dic[j] = dic[j].strip()
    if dic[j].endswith('c') and (dic[j].startswith('a') or dic[j].startswith('A')):
        print(dic[j])
print(dic)

for i in dic.values() :
    i = i.strip()
    if i.endswith('c') and (i.startswith('a') or i.startswith('A')):
        print(dic[j])
print(dic)