jdk1.8 HashMap的扩容resize()方法详解

       

 /**
     * Initializes or doubles table size.  If null, allocates in
     * accord with initial capacity target held in field threshold.
     * Otherwise, because we are using power-of-two expansion, the
     * elements from each bin must either stay at same index, or move
     * with a power of two offset in the new table.
     *  @return the table
     * 
     * 
     *
     * 初始化或者翻倍表大小。
     * 如果表为null,则根据存放在threshold变量中的初始化capacity的值来分配table内存
     * (这个注释说的很清楚,在实例化HashMap时,capacity其实是存放在了成员变量threshold中,
     * 注意,HashMap中没有capacity这个成员变量)
     * 。如果表不为null,由于我们使用2的幂来扩容,
     * 则每个bin元素要么还是在原来的bucket中,要么在2的幂中
     * 
     * 此方法功能:初始化或扩容
     */
    final Node<K,V>[] resize() {
        Node<K,V>[] oldTab = table;
        int oldCap = (oldTab == null) ? 0 : oldTab.length;
        int oldThr = threshold;
        //新的容量值,新的扩容阀界值
        int newCap, newThr = 0;
        //oldTab!=null,则oldCap>0
        if (oldCap > 0) {
            //如果此时oldCap>=MAXIMUM_CAPACITY(1 << 30),表示已经到了最大容量,这时还要往map中放数据,则阈值设置为整数的最大值 Integer.MAX_VALUE,直接返回这个oldTab的内存地址。 
            if (oldCap >= MAXIMUM_CAPACITY) {
                threshold = Integer.MAX_VALUE;
                return oldTab;
            }
            //如果(当前容量*2<最大容量&&当前容量>=默认初始化容量(16))
            //并将将原容量值<<1(相当于*2)赋值给 newCap
            else if ((newCap = oldCap << 1) < MAXIMUM_CAPACITY && 
                     oldCap >= DEFAULT_INITIAL_CAPACITY)
                //如果能进来证明此map是扩容而不是初始化
                //操作:将原扩容阀界值<<1(相当于*2)赋值给 newThr
                newThr = oldThr << 1; // double threshold
        }
        else if (oldThr > 0) // initial capacity was placed in threshold
            //进入此if证明创建map时用的带参构造:public HashMap(int initialCapacity)或 public HashMap(int initialCapacity, float loadFactor)
            //注:带参的构造中initialCapacity(初始容量值)不管是输入几都会通过 “this.threshold = tableSizeFor(initialCapacity);”此方法计算出接近initialCapacity参数的2^n来作为初始化容量(初始化容量==oldThr)
            newCap = oldThr;
        else {               // zero initial threshold signifies using defaults
            //进入此if证明创建map时用的无参构造:
            //然后将参数newCap(新的容量)、newThr(新的扩容阀界值)进行初始化
            newCap = DEFAULT_INITIAL_CAPACITY;
            newThr = (int)(DEFAULT_LOAD_FACTOR * DEFAULT_INITIAL_CAPACITY);
        }
        if (newThr == 0) {
            
            //进入此if有两种可能
            // 第一种:进入此“if (oldCap > 0)”中且不满足该if中的两个if
            // 第二种:进入这个“else if (oldThr > 0)”
            
            //分析:进入此if证明该map在创建时用的带参构造,如果是第一种情况就说明是进行扩容且oldCap(旧容量)小于16,如果是第二种说明是第一次put
            float ft = (float)newCap * loadFactor;
            //计算扩容阀界值
            newThr = (newCap < MAXIMUM_CAPACITY && ft < (float)MAXIMUM_CAPACITY ?
                      (int)ft : Integer.MAX_VALUE);
        }
        threshold = newThr;
        @SuppressWarnings({"rawtypes","unchecked"})
            Node<K,V>[] newTab = (Node<K,V>[])new Node[newCap];
        table = newTab;
        //如果“oldTab != null”说明是扩容,否则直接返回newTab
        if (oldTab != null) {
            for (int j = 0; j < oldCap; ++j) {
                Node<K,V> e;
                if ((e = oldTab[j]) != null) {
                    oldTab[j] = null;
                    
                    if (e.next == null)
                        newTab[e.hash & (newCap - 1)] = e;
                    else if (e instanceof TreeNode)
                        //如果该元素是TreeNode的实例
                        ((TreeNode<K,V>)e).split(this, newTab, j, oldCap);
                    else { // preserve order
                        Node<K,V> loHead = null, loTail = null;//此对象接收会放在原来位置
                        Node<K,V> hiHead = null, hiTail = null;//此对象接收会放在“j + oldCap”(当前位置索引+原容量的值)
                        Node<K,V> next;
                        do {
                            next = e.next;
                            //以下是扩容操作的核心,详情见我的博客:https://www.cnblogs.com/shianliang/p/9204942.html
                            if ((e.hash & oldCap) == 0) {
                                
                                if (loTail == null)
                                    loHead = e;
                                else
                                    loTail.next = e;
                                loTail = e;
                            }
                            else {
                                if (hiTail == null)
                                    hiHead = e;
                                else
                                    hiTail.next = e;
                                hiTail = e;
                            }
                        } while ((e = next) != null);
                        if (loTail != null) {
                            loTail.next = null;
                            newTab[j] = loHead;
                        }
                        if (hiTail != null) {
                            hiTail.next = null;
                            newTab[j + oldCap] = hiHead;
                        }
                    }
                }
            }
        }
        return newTab;
    }

 

posted @ 2017-03-27 11:43  史安良  阅读(5610)  评论(0编辑  收藏  举报