4-12

源程序1:

#include<stdio.h>
int main(void)
{
    int child,men,women;
    for(men=0;men<=45;men++)
        for(women=0;women<=45;women++)
            for(child=0;child<=45;child++)
                if(men+women+child==45 && men*3 +women*2 +child*0.5==45)
                    printf("men=%d,women=%d,child=%d\n",men,women,child);
    return 0;
}

源程序 2:

posted @ 2013-10-04 15:00  韵文  阅读(91)  评论(0编辑  收藏  举报