php js表单登陆验证

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>项目后台管理系统</title>
<link rel="stylesheet" href="__PUBLIC__/css/login.css" />
<script type="text/javascript" src="__PUBLIC__/js/jquery.min.js"></script>
<script type="text/javascript">
function $(id)
{
   return document.getElementById(id);
}
//验证姓名
function checkname(){
   var name=$("admin_name").value;
   if(name=='')
   {
      $('s1').innerHTML='姓名不能为空';
      $('s1').style.color='red';
      return false;
   }
   else
   {
       $('s1').innerText='ok';
        $('s1').style.color='green';
       return true;
   }
}
//验证密码
function checkpwd(){
    var password=$("password").value;
   if(password=='')
   {
      $('s2').innerHTML='密码不能为空';
   $('s2').style.color='red';
      return false;
   }
   else
   {
       $('s2').innerHTML='ok';
       $('s2').style.color='green';
       return true;
   }

}
//验证所有表单提交
function checkall()
{
   if(checkname()&&checkpwd())
   {
       return true;
   }
   else
   {
       return false;
   }
}
</script>
</head>

<body class="b">
<div class="lg">
<form action="__URL__/dologin" method="POST" onsubmit="return checkall();">
    <div class="lg_top"></div>
    <div class="lg_main">
        <div class="lg_m_1">
        <input name="admin_name" value="" class="ur" id="admin_name" onblur="checkname();"/><span id='s1'></span>
        <input name="password" type="password" value="" class="pw" id="password" onblur="checkpwd();"/><span id='s2'></span>
        </div>
    </div>
    <div class="lg_foot">
    <input type="submit" value="Login In" class="bn" /></div>
</form>
</div>

</body>
</html>

posted @ 2016-05-18 21:43 Love满天星阅读(345) 评论(0) 收藏举报

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