prim算法找最小生成树
先定义图类:
class MGraph {
int verxs;// 表示图的节点个数
char[] data;// 存放节点数据
int[][] weight;// 存放边,就是我们的邻接矩阵
public MGraph(int verxs) {
this.verxs = verxs;
data = new char[verxs];
weight = new int[verxs][verxs];
}
}
然后是创建最小生成树的类:
//创建最小生成树->村庄的图
class MinTree {
/**
* 创建图的邻接矩阵
* @param graph 图对象
* @param verxs 图对应的顶点个数
* @param data 图的各个顶点的值
* @param weight 图的邻接矩阵
*/
public void createGraph(MGraph graph, int verxs, char[] data, int[][] weight) {
int i, j;
for (i = 0; i < verxs; i++) {// 顶点
graph.data[i] = data[i];
for (j = 0; j < verxs; j++) {
graph.weight[i][j] = weight[i][j];
}
}
}
// 显示图的邻接矩阵
public void showGraph(MGraph graph) {
for (int[] link : graph.weight) {
System.out.println(Arrays.toString(link));
}
}
/**
* 编写prim算法,得到最小生成树
* @param graph 图
* @param v 表示从图的第几个顶点开始生成
*/
public void prim(MGraph graph, int v) {
int[] visited = new int[graph.verxs];//标记节点是否被访问过
visited[v] = 1;
//用h1和h2记录两个顶点的下标
int h1 = -1;
int h2 = -1;
int minWeight = 10000;
for(int k = 1; k < graph.verxs; k++) {
//确定每一次生成的子图和哪个节点的距离最近
for(int i = 0; i < graph.verxs; i++) {
for(int j = 0; j < graph.verxs; j++) {
if(visited[i] == 1 && visited[j] == 0 && graph.weight[i][j] < minWeight) {
minWeight = graph.weight[i][j];
h1 = i;
h2 = j;
}
}
}
//找到一条边是最小
System.out.println("边<" + graph.data[h1] + "," + graph.data[h2] + "> 权值:" + minWeight);
//将当前这个节点标为已经访问
visited[h2] = 1;
//重新设置minWeight为10000
minWeight = 10000;
}
}
}
最后是主类:
public class PrimAlgorithm {
public static void main(String[] args) {
char[] data = new char[] {'A','B','C','D','E','F','G'};
int verxs = data.length;
int[][] weight = new int[][] {//10000表示两个点不连通
{10000,5,7,10000,10000,10000,2},
{5,10000,10000,9,10000,10000,3},
{7,10000,10000,10000,8,10000,10000},
{10000,9,10000,10000,10000,4,10000},
{10000,10000,8,10000,10000,5,4},
{10000,10000,10000,4,5,10000,6},
{2,3,10000,10000,4,6,10000}
};
MGraph mGraph = new MGraph(verxs);
MinTree minTree = new MinTree();
minTree.createGraph(mGraph, verxs, data, weight);
// minTree.showGraph(mGraph);
minTree.prim(mGraph, 0);
}
}

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