lua 删除table元素

 

tab1 = { key1 = "val1", key2 = "val2", "val3" }
for k, v in pairs(tab1) do
    print(k .. " - " .. v)
end
print("\nafter\n") 
tab1.key1 = nil
for k, v in pairs(tab1) do
    print(k .. " - " .. v)
end

输出:

1 - val3
key2 - val2
key1 - val1

after

1 - val3
key2 - val2

 

posted @ 2018-11-18 15:45  anobscureretreat  阅读(376)  评论(0编辑  收藏  举报