let turtles = ['Leo','Raph','Mikey','Don']; console.log(...turtles);
let turtles = ['Leo','Raph','Mikey','Don']; let [first,second,...others] = turtles; console.log(first,second,others);
posted on 2018-06-15 16:47 沙滩海风 阅读(178) 评论(0) 收藏 举报
博客园 © 2004-2025 浙公网安备 33010602011771号 浙ICP备2021040463号-3