PTA连续因子

一、题目描述

 

 二、解题思路

　　我们枚举n的因子，然后枚举这个因子的最大长度，然后做个标记。最后在输出答案的时候反推就可以了。

三、代码实现

 1 #include "bits/stdc++.h"
 2 #define PII pair<int,int>
 3 #define rep(i,z,n) for(int i = z;i <= n; i++)
 4 #define per(i,n,z) for(int i = n;i >= z; i--)
 5 #define ll long long
 6 #define db double
 7 #define vi vector<int>
 8 #define debug(x) cerr << "!!!" << x << endl;
 9 using namespace std;
10 inline ll read()
11 {
12     ll s,r;
13     r = 1;
14     s = 0;
15     char ch = getchar();
16     while(ch < '0' || ch > '9'){
17         if(ch == '-')
18             r = -1;
19         ch = getchar();
20     }
21     while(ch >= '0' && ch <= '9'){
22         s = (s << 1) + (s << 3) + (ch ^ 48);
23         ch = getchar();
24     }
25     return s * r;
26 }
27 inline void write(ll x)
28 {
29     if(x < 0) putchar('-'),x = -x;
30     if(x > 9) write(x / 10);
31     putchar(x % 10 + '0');
32 }
33 bool prime(int k)
34 {
35     if(k == 1)
36         return false;
37     for(int i = 2;i <= sqrt(k);i++)
38         if(k % i == 0)
39             return false;
40     return true;
41 }
42 int n;
43 int maxsize;
44 int pos = 0;
45 void solve(){
46     for(int i = 2;i <= sqrt(n);i++){
47         int j = i;
48         int cnt = 0;
49         int tt = n;
50         while(tt % j == 0){
51             tt /= j;
52             cnt++;
53             j++;
54         }
55         if(cnt > maxsize){
56             pos = i;
57             maxsize = cnt;
58         }
59     }
60 }
61 int main()
62 {
63     n = read();
64     if(prime(n)){
65         cout << 1 << endl;
66         cout << n << endl;
67         return 0;
68     }
69     solve();
70     if(maxsize){
71         cout << maxsize << endl;
72     for(int i = 1;i <= maxsize;i++){
73         if(i == 1)
74             cout << pos;
75         else
76             cout << '*' << pos + i - 1;
77     }    
78     }
79     return 0;
80 }
posted @ 2022-03-19 16:27  scannerkk  阅读(187)  评论(0)    收藏  举报