实验六
4.
#define _CRT_SECURE_NO_WARNINGS #include<stdio.h> #include<stdlib.h> #define N 10 typedef struct { char isbn[20]; char name[80]; char author[80]; double sales_price; int sales_count; }Book; void output(Book x[], int n); void sort(Book x[], int n); double sales_amount(Book x[], int n); int main() { Book x[N]= {{ "978-7-229-14156-1", "源泉", "安.兰德", 84, 59 }, { "978-7-5133-5261-1", "李白来到旧金山", "谭夏阳", 48, 16 }, { "978-7-5617-4347-8", "陌生人日记", "周怡芳", 72.6, 27 }, { "978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49 }, { "978-7-5046-9568-0", "数据化决策", "道格拉斯·W·哈伯德", 49, 42 }, { "978-7-5133-4388-6", "美好时代的背后", "凯瑟琳.布", 34.5, 39 }, { "978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55 }, { "978-7-5321-5691-7", "何为良好生活", "陈嘉映", 29.5 , 31 }, { "978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42 }, { "978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44 }}; printf("图书销量排名:\n"); sort(x, N); output(x, N); printf("\n图书销售总额:%.2f\n", sales_amount(x, N)); return 0; } void output(Book x[], int n) {int i = 0; for (i = 0; i < n; i++) printf("%s %-28s %-24s %-15lf %d\n", x[i].isbn, x[i].name, x[i].author, x[i].sales_price, x[i].sales_count); } void sort(Book x[], int n) { int i = 0, j = 0; Book t; for (i = 0; i < n - 1; i++) for (j = 0; j < n - i - 1; j++) if (x[j].sales_count < x[j + 1].sales_count) { t = x[j]; x[j] = x[j + 1]; x[j + 1] = t; } } double sales_amount(Book x[], int n) { int i = 0, j = 0; double sum = 0; for (i = 0; i < n; i++) sum = sum + (double)(x[i].sales_count * x[i].sales_price); return sum; }
5.
#include <stdio.h> typedef struct { int year; int month; int day; } Date; void input(Date *pd); int day_of_year(Date d); int compare_dates(Date d1, Date d2); void test1() { Date d; int i; printf("输入日期:(以形如2023-12-11这样的形式输入)\n"); for(i = 0; i < 3; ++i) { input(&d); printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d)); } } void test2() { Date Alice_birth, Bob_birth; int i; int ans; printf("输入Alice和Bob出生日期:(以形如2023-12-11这样的形式输入)\n"); for(i = 0; i < 3; ++i) { input(&Alice_birth); input(&Bob_birth); ans = compare_dates(Alice_birth, Bob_birth); if(ans == 0) printf("Alice和Bob一样大\n\n"); else if(ans == -1) printf("Alice比Bob大\n\n"); else printf("Alice比Bob小\n\n"); } } int main() { printf("测试1: 输入日期, 打印输出这是一年中第多少天\n"); test1(); printf("\n测试2: 两个人年龄大小关系\n"); test2(); } void input(Date *pd) { scanf("%d-%d-%d",&pd->year,&pd->month,&pd->day); } int day_of_year(Date d) { int date=0; switch(d.month) { case 1:date=d.day;break; case 2:date=31+d.day;break; case 3:date=60+d.day;break; case 4:date=91+d.day;break; case 5:date=121+d.day;break; case 6:date=152+d.day;break; case 7:date=182+d.day;break; case 8:date=213+d.day;break; case 9:date=244+d.day;break; case 10:date=274+d.day;break; case 11:date=305+d.day;break; case 12:date=335+d.day;break; } if (d.year%4!=0&&d.month>2) date--; return date; } int compare_dates(Date d1, Date d2) { int ans; if (d1.year<d2.year) ans=-1; else if (d1.year>d2.year) ans=1; else { if (d1.month<d2.month) ans=-1; else if (d1.month>d2.month) ans=1; else { if (d1.day<d2.day) ans=-1; else if (d1.day>d2.day) ans=1; else ans=0; } } return ans; }
6.
#include <stdio.h> #include <string.h> enum Role {admin, student, teacher}; typedef struct { char username[20]; char password[20]; enum Role type; } Account; void output(Account x[], int n); int main() { Account x[] = {{"A1001", "123456", student}, {"A1002", "123abcdef", student}, {"A1009", "xyz12121", student}, {"X1009", "9213071x", admin}, {"C11553", "129dfg32k", teacher}, {"X3005", "921kfmg917", student}}; int n; n = sizeof(x)/sizeof(Account); output(x, n); return 0; } void output(Account x[], int n) { int i,j; for (i=0;i<n;i++) { printf("%-20s",x[i].username); for (j=0;j<strlen(x[i].password);j++) printf("*"); for (;j<20;j++) printf(" "); switch(x[i].type) { case 0:printf("admin");break; case 1:printf("student");break; case 2:printf("teacher");break; } printf("\n"); } }
7.
#include <stdio.h>
#include <string.h>
typedef struct {
char name[20]; // 姓名
char phone[12]; // 手机号
int vip; // 是否为紧急联系人，是取1；否则取0
} Contact;
// 函数声明
void set_vip_contact(Contact x[], int n, char name[]); // 设置紧急联系人
void output(Contact x[], int n); // 输出x中联系人信息
void display(Contact x[], int n); // 按联系人姓名字典序升序显示信息，紧急联系人最先显示
#define N 10
int main() {
Contact list[N] = {{"刘一", "15510846604", 0},
{"陈二", "18038747351", 0},
{"张三", "18853253914", 0},
{"李四", "13230584477", 0},
{"王五", "15547571923", 0},
{"赵六", "18856659351", 0},
{"周七", "17705843215", 0},
{"孙八", "15552933732", 0},
{"吴九", "18077702405", 0},
{"郑十", "18820725036", 0}};
int vip_cnt, i;
char name[20];
printf("显示原始通讯录信息: \n");
output(list, N);
printf("\n输入要设置的紧急联系人个数: ");
scanf("%d", &vip_cnt);
printf("输入%d个紧急联系人姓名:\n", vip_cnt);
for(i = 0; i < vip_cnt; ++i) {
scanf("%s", name);
set_vip_contact(list, N, name);
}
printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
display(list, N);
return 0;
}
// 补足函数set_vip_contact实现
// 功能：将联系人数组x中，联系人姓名与name一样的人，设置为紧急联系人（即成员vip值设为1）
void set_vip_contact(Contact x[], int n, char name[]) {
int i;
for(i=0;i<n;i++){
if(strcmp(x[i].name,name)==0)
x[i].vip=1;
}
}
// 补足函数display实现
// 功能: 显示联系人数组x中的联系人信息
// 按姓名字典序升序显示, 紧急联系人显示在最前面
void display(Contact x[], int n) {
int i,j=0,k,a=0,b;
Contact t[N],s[N],m;
for(i=0;i<n;i++){
if(x[i].vip)
t[j++]=x[i];
else
s[a++]=x[i];
}
k=j;
for(i=0;i<k-1;i++){
for(j=i+1;j<k;j++){
if(strcmp(t[i].name ,t[j].name )>0){
m=t[i];
t[i]=t[j];
t[j]=m;
}
}
}
b=a;
for(i=0;i<b-1;i++){
for(j=i+1;j<b;j++){
if(strcmp(s[i].name ,s[j].name )>0){
m=s[i];
s[i]=s[j];
s[j]=m;
}
}
}
for(i=0;i<k;i++)
x[i]=t[i];
for(j=0;j<b;j++)
x[i++]=s[j];
output(x,n);
}
void output(Contact x[], int n) {
int i;
for(i = 0; i < n; ++i) {
printf("%-10s%-15s", x[i].name, x[i].phone);
if(x[i].vip)
printf("%5s", "*");
printf("\n");
}
}
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