实验4

#include<stdio.h>
const int N=4;
int main()
{
    int a[N]={2,0,2,1};
    char b[N]={'2','0','1','1'};
    int i;
    printf("sizeof(int)=%d\n",sizeof(int));
    printf("sizeof(char)=%d\n",sizeof(char));
    printf("\n");
    for(i=0;i<N;++i)
    printf("%x:%d\n",&a[i],&a[i]);
    printf("\n");
    for(i=0;i<N;++i)
    printf("%x:%c\n",&b[i],&b[i]);
    return 0;
 }

 

#include<stdio.h>
 
int main()
{
    int a[2][3]={{1,2,3},{4,5,6}};
    char b[2][3]={{'1','2','3'},{'4','5','6'}};
    int i,j;
    for(i=0;i<2;++i)
        for(j=0;j<3;++j)
            printf("%x:%d\n",&a[i][j],&a[i][j]);
    printf("\n");
    for(i=0;i<2;++i)
        for(j=0;j<3;j++)
            printf("%x:%c\n",&b[i][j],&b[i][j]);
    return 0;
 }

 

#include<stdio.h>
#define N 1000
int fun(int n, int m, int bb[N])
{
    int i, j, k = 0, flag;
    for (j = n; j <= m; j++)
    {
        flag = 1;
        for (i = 2; i < j; i++)
            if (j % i == 0)
            {
                flag = 0;
                break;
            }
        if (flag)
            bb[k++] = j;
    }
    return k;
}
int main()
{
    int n = 0, m = 0, i, k, bb[N];

    scanf_s("%d", &n);
    scanf_s("%d", &m);

    for (i = 0; i < m - n; i++)
        bb[i] = 0;

    k = fun(n, m, bb);

    for (i = 0; i < k; i++)
        printf("%4d", bb[i]);

    return 0;
}

 

#include <stdio.h>
const int N = 5;
int find_max(int x[], int n);
void input(int x[], int n);
void output(int x[], int n);
int main()
{
int a[N];
int max;
input(a, N); // 调用input完成数组输入
output(a, N); // 调用output输出数组元素值
max = find_max(a, N); // 调用find_max查找数组a的最大值
printf("max = %d\n", max);
return 0;
}
// 函数定义
// 功能：为数组x的n个元素输入数值
void input(int x[], int n)
{
int i;
for (i = 0; i < n; ++i)
scanf("%d", &x[i]);
}

 

#include <stdio.h>
void dec2n(int x, int n); // 函数声明
int main()
{
    int x;
    printf("输入一个十进制整数: ");
    scanf_s("%d", &x);
    dec2n(x, 2);
    dec2n(x, 8);
    dec2n(x, 16);
    return 0;
}
void dec2n(int x, int n) {
    int i, k = 0, j, m, a[1000];
    while (x != 0)
    {
        m = x % n;
        a[k] = m;
        k++;
        x = x / n;
    }
    for (j = k - 1; j >= 0; j--) {
        if (a[j] <= 9)
            printf("%d", a[j]);
        else switch (a[j]) {
        case 10:printf("A"); break;
        case 11:printf("B"); break;
        case 12:printf("C"); break;
        case 13:printf("D"); break;
        case 14:printf("E"); break;
        case 15:printf("F"); break;
        }
    }
    printf("\n");
}

 

#include<stdio.h>
int main()
{
    int i, j, n;
    printf("Enter n:");
    while (1) {
        scanf_s("%d", &n);
        for (j = 1; j <= n; j++)
        {
            for (i = 1; i <= n; i++)
            {
                if (i <= j)
                    printf("%2d", i);
                else
                    printf("%2d", j);
            }
            printf("\n");
        }
    }
    return 0;
}