阅读程序作业5(from 12 届普及组 2008、12、3)
1. Program ex301;
var
u:array[0..3] of integer;
i,a,b,x,y:integer;
begin
y:=10;
for i:=0 to 3 do
read(u[i]);
a:=(u[0]+u[1]+u[2]+u[3]) div 7;
b:=u[0] div ((u[1]-u[2]) div u[3]);
x:=(u[0]+a+2)-u[(u[3]+3) mod 4];
if (x>10) then
y:=y+(b*100-u[3]) div (u[u[0] mod 3]*5)
else
y:=y+20+(b*100-u[3]) div (u[u[0] mod 3]*5);
writeln (x,',',y);
end. {*注:本例中,给定的输入数据可以避免分母为 0 或下标越界。 }
输入:9 3 9 4输出:_______________
2.Program ex302;
const
m:array[0..4] of integer=(2,3,5,7,13);
var
i,j:integer;
t: longint;
begin
for i:=0 to 4 do
begin
t:=1;
for j:=1 to m[i]-1 do
t:=t*2;
t:=(t*2-1)*t;
write (t,' ');
end;
writeln;
end.
输出:____________________
3.Program ex303;
Const
NN=7;
Type
Arr1=array[0..30] of char;
var
s:arr1;
k,p:integer;
Function fun(s:arr1; a:char;n:integer):integer;
var
j:integer;
begin
j:=n;
while (a<s[j])and(j>0) do dec(j);
fun:=j;
end;
begin
for k:=1 to NN do
s[k]:=chr(ord('A')+2*k+1);
k:=fun(s,'M',NN);
writeln(k);
end.
输出:_____________
4.program ex304;
var
x,x2:longint;
procedure digit(n,m:longint);
var n2:integer;
begin
if(m>0) then
begin
n2:=n mod 10;
write(n2:2);
if(m>1) then digit(n div 10,m div 10);
n2:=n mod 10;
write(n2:2);
end;
end;
begin
writeln('Input a number:');
readln(x);
x2:=1;
while(x2<x) do x2:=x2*10;
x2:=x2 div 10;
digit(x,x2);
writeln;
end.
输入:9734526
输出:______________________________
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