Leetcode---1. Two Sum

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

class Solution {
    public int[] twoSum(int[] nums, int target) {
        Map<Integer, Integer> map = new HashMap<>();
        int[] res = new int[2];
        for(int i = 0; i < nums.length; i++) {
            int another = target - nums[i];
            if(map != null && map.containsKey(another) && map.get(another) != i) {
                res[0] = map.get(another);
                res[1] = i;
                break;
            }
            map.put(nums[i], i);
        }
        return res;
    }
}

  

posted on 2018-06-24 09:56  Hugh_Sun  阅读(117)  评论(0编辑  收藏  举报

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