实验6

实验任务4

源代码

#include<stdio.h>
#include<stdlib.h>
#define N 10

typedef struct{
    char isbn[20];
    char name[80];
    char author[80];
    double sales_prince;
    int sales_count;
}Book;

void output(Book x[],int n);//输出
void sort(Book x[],int n);//按销售量排名
double sales_amount(Book x[],int n);//计算销售总额

int main(){
    Book x[N] = {{"978-7-5327-6082-4","门将之死","罗纳德.伦",42,51},
                 {"978-7-308-17047-5","自由与爱之地：入以色列记","云也退",49,30},
                 {"978-7-5404-9344-8","伦敦人","克莱格泰勒",68,27},
                   {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90},
                 {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
                 {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
                 {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
                 {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
                 {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5,55},
                 {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}};

    printf("图书销量排名（按销售册数：\n）");
    sort(x,N);

    output(x,N);

    printf("\n图书销售总额：%.2f\n",sales_amount(x,N));

    system("pause");
    return 0;
}

void output(Book x[],int n){
    int i;
    printf("ISBN号\t\t书名\t\t作者\t售价\t销售册\n");
    for(i = 0;i < n;i++){
        printf("%s\t\t%s\t\t%s\t%g\t%d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_prince,  x[i].sales_count);
        
    }
}

void sort(Book x[],int n){
    int i,j;
    Book t;
    for(i = 0;i < n;i++){
        for(j=0;j<n;j++){
            if(x[j].sales_count<x[j+1].sales_count){
                t = x[j];
                x[j] = x[j+1];
                x[j+1] = t;
            }
        }
    }
    
}

double sales_amount(Book x[],int n){
    double sum=0.0;
    int i;
    for(i=0;i<n;i++){
        sum += x[i].sales_count * x[i].sales_prince;
    }
    return sum;
}

 

运行结果截图

 

实验任务5

源代码

#include<stdio.h>
#include<stdlib.h>

typedef struct{
    int year;
    int month;
    int day;
}Date;

void input(Date *pd);//输入日期
int day_of_year(Date d);//返回日期d是这一年的第多少天
int compare_dates(Date d1,Date d2);//比较两个日期，d1在d2前，返回-1；在之后，返回1；相同，返回0。

void test1(){
    Date d;
    int i;
    printf("输入日期：（以形如2025-12-19这样的形式输入）\n");
    for(i = 0;i < 3;++i){
        input(&d);
        printf("%d-%02d-%02d是这一年中第%d天\n\n",d.year,d.month,d.day,day_of_year(d));
    }
}

void test2(){
    Date Alice_birth,Bob_birth;
    int i;
    int ans;

    printf("输入Alice和Bob的出生日期:(以形如2025-12-19这样的形式输入)\n");
    for(i=0;i<3;++i){
        input(&Alice_birth);
        input(&Bob_birth);
        ans = compare_dates(Alice_birth,Bob_birth);

        if(ans == 0)
            printf("Alice和Bob一样大\n\n");
        else if(ans == -1)
            printf("Alice比Bob大\n\n");
        else
            printf("Alice比Bob小\n\n");
    }

}

int main(){
    printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
    test1();

    printf("\n测试2: 两个人年龄大小关系\n");
    test2();

    system("pause");
    return 0;
}

void input(Date *pd){
    scanf("%d-%02d-%02d",&pd->year,&pd->month,&pd->day);
}


int day_of_year(Date d){
    int i;
    int sum = 0;
    if(d.month >= 12)
        sum +=334;
    else if(d.month >= 11)
        sum +=304;
    else if(d.month >= 10)
        sum +=273;
    else if(d.month >= 9)
        sum +=243;
    else if(d.month >= 8)
        sum +=212;
    else if(d.month >= 7)
        sum +=181;
    else if(d.month >= 6)
        sum +=151;
    else if(d.month >= 5)
        sum +=120;
    else if(d.month >= 4)
        sum +=90;
    else if(d.month >= 3)
        sum +=59;
    else if(d.month >= 2)
        sum +=31;
    else
        sum +=0;

    if(d.month >= 3 && ((d.year % 4 == 0 && d.year % 100 != 0)||d.year % 400 == 0))
        sum +=1;

    sum +=d.day;
    return sum;
}

int compare_dates(Date d1,Date d2){
    if(d1.year == d2.year){
        if(d1.month == d2.month){
            if(d1.day == d2.day)
                return 0;
            else if(d1.day < d2.day)
                return -1;
            else
                return 1;
        }
        else if(d1.month < d2.month)
            return -1;
        else
            return 1;
        }
    else if(d1.year < d2.year)
        return -1;
    else
        return 1;
    

}

 

运行结果截图

 

实验任务6

源代码

#include<stdio.h>
#include<stdlib.h>
#include<string.h>

enum Role{admin,student,teacher};

typedef struct{
    char username[20];
    char password[20];
    enum Role type;
} Account;

void output(Account x[],int n);
const char* role_to_str(enum Role m){
    switch(m){
    case 0:return "admin";
    case 1:return "student";
    case 2:return "teacher";
    default:return "unknown";
    }
}

int main(){
    Account x[] =  {{"A1001", "123456", student},
                    {"A1002", "123abcdef", student},
                    {"A1009", "xyz12121", student},
                    {"X1009", "9213071x", admin},
                    {"C11553", "129dfg32k", teacher},
                    {"X3005", "921kfmg917", student}};
    int n;
    n = sizeof(x)/sizeof(Account);
    output(x,n);

    system("pause");
    return 0;
}

void output(Account x[],int n){
    int i,j;
    int length;
    for(i=0;i<n;i++){
        printf("%s\t",x[i].username);
        length = strlen(x[i].password);
        for(j=0;j<length;j++){
            printf("*");
        }
        
        printf("\t%s\n",role_to_str(x[i].type));
    }

}

 

运行结果截图

 

实验任务7

源代码

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define N 10

typedef struct{
    char name[20];
    char phone[12];
    int vip;
}Contact;

void set_vip_contact(Contact x[],int n,char name[]);
void output(Contact x[],int n);
void display(Contact x[],int n);



int main(){
    Contact list[N] =  {{"刘一", "15510846604", 0},
                        {"陈二", "18038747351", 0},
                        {"张三", "18853253914", 0},
                        {"李四", "13230584477", 0},
                        {"王五", "15547571923", 0},
                        {"赵六", "18856659351", 0},
                        {"周七", "17705843215", 0},
                        {"孙八", "15552933732", 0},
                        {"吴九", "18077702405", 0},
                        {"郑十", "18820725036", 0}};
    int vip_cnt,i;
    char name[20];

    printf("显示原始通讯录信息：\n");
    output(list,N);

    printf("\n输入要设置的紧急联系人个数：");
    scanf("%d",&vip_cnt);
    printf("输入%d个紧急联系人姓名：\n",vip_cnt);
    for(i=0;i<vip_cnt;++i){
        scanf("%s",name);
        set_vip_contact(list,N,name);
    }

    printf("\n显示通讯录列表：（按姓名字典升序排列，紧急联系人最先显示）\n");
    display(list,N);

    system("pause");
    return 0;
}

void output(Contact x[],int n){
    int i;

    for(i=0;i<n;++i){
        printf("%-10s%-15s",x[i].name,x[i].phone);
        if(x[i].vip)
            printf("%5s","*");
        printf("\n");
    }
}

void set_vip_contact(Contact x[],int n,char name[]){
    int i;
    for(i=0;i<n;i++){
        if(strcmp(x[i].name,name) == 0)
            x[i].vip = 1;
            
    }
}

void display(Contact x[],int n){
    int i,j;
    Contact t;
    for(i=0;i<n-1;i++){
        for(j=0;j<n-1-i;j++){
            if(x[j].vip < x[j+1].vip || (x[j].vip == x[j+1].vip && strcmp(x[j].name,x[j+1].name)>0)){
                t = x[j];
                x[j] = x[j+1];
                x[j+1] = t;
            }
        }
    }
    for(i = 0;i<n;i++){
        printf("%s\t%s\t%s\n",x[i].name,x[i].phone,x[i].vip?"*":" ");
    }
}

 

运行结果截图