290. Word Pattern

problem

Given a pattern and a string str, find if str follows the same pattern.

Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str.

Examples:
pattern = "abba", str = "dog cat cat dog" should return true.
pattern = "abba", str = "dog cat cat fish" should return false.
pattern = "aaaa", str = "dog cat cat dog" should return false.
pattern = "abba", str = "dog dog dog dog" should return false.
Notes:
You may assume pattern contains only lowercase letters, and str contains lowercase letters separated by a single space.

solution

思路:被对比元素按次序 用 0,1,2,3表示(分别以字符,单词为单位),将两者转换为格式列表 ,然后对比列表

同构字符串问题,其他语言中可能用到哈希

class Solution(object):
    def wordPattern(self, pattern, str):
        s = pattern
        t = str.split()
        return map(s.find, s) == map(t.index, t)
posted @ 2016-09-27 21:24  Salmd  阅读(86)  评论(0)    收藏  举报