正向循环删除元素

删除所有匹配的元素

function RemoveMatchItems(list, matchFunc)
    local removeCt = 0
    local ct = #list
    local i = 1
    while i <= ct do
        if matchFunc(list[i]) then
            table.remove(list, i)
            i = i - 1
            ct = ct - 1
            removeCt = removeCt + 1
        end
        i = i + 1
    end
    return removeCt
end

测试代码

local list = { "a", "b", "c" }
local ct = RemoveMatchItems(list, function(item)
    return "b" == item
end)
print(ct, list[1], list[2]) --1 a c