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ACM s1124yy
守りたいものが 強くさせること
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LA 4992 Jungle Outpost(半平面交)

Jungle Outpost

【题目链接】Jungle Outpost

【题目类型】半平面交

&题解:

蓝书282 我自己写的代码居然AC了!!!
刘汝佳的说要right要-3什么的,还要特判3,我感觉就不需要,所以我就没写,交了一发,想着应会wa吧,结果居然tmA了!!!

&代码:

#include <cstdio>
#include <algorithm>
#include <cmath>
#include <vector>
using namespace std;

struct Point {
	double x, y;
	Point(double x = 0, double y = 0): x(x), y(y) {}
};
typedef Point Vector;

Vector operator + (Vector A, Vector B) { return Vector(A.x + B.x, A.y + B.y); }
Vector operator - (Vector A, Vector B) { return Vector(A.x - B.x, A.y - B.y); }
Vector operator * (Vector A, double p) { return Vector(A.x * p, A.y * p); }
bool operator < (Point a, Point b) { return a.x < b.x || (a.x == b.x && a.y < b.y); }
double Cross(Vector A, Vector B) { return A.x * B.y - A.y * B.x; }

double PolygonArea(vector<Point> p) {
	int n = p.size();
	double ans = 0;
	for(int i = 1; i < n - 1; i++) {
		ans += Cross(p[i] - p[0], p[i + 1] - p[0]);
	}
	return ans / 2;
}

struct Line {
	Point p, v;
	double ang;
	Line() {}
	Line(Point p, Vector v): p(p), v(v) { ang = atan2(v.y, v.x); }
	bool operator <(const Line& l) const {
		return ang < l.ang;
	}
};

const double eps = 1e-9;

bool OnLeft(Line l, Point p) {
	//bug 是p-l.p  不是l.p-p
	return Cross(l.v, p - l.p) > 0;
}
Point LineInter(Line a, Line b) {
	Vector u = a.p - b.p;
	double t = Cross(b.v, u) / Cross(a.v, b.v);
	return a.p + a.v * t;
}

vector<Point> HalfplaneIntersection(vector<Line> L) {
	int n = L.size();
	sort(L.begin(), L.end());
	int first, last;
	vector<Point> p(n), ans;
	vector<Line> que(n);
	que[first = last = 0] = L[0];
	for(int i = 1; i < n; i++) {
		while(first < last && !OnLeft(L[i], p[last - 1])) last--;
		while(first < last && !OnLeft(L[i], p[first])) first++;
		que[++last] = L[i];
		if(fabs(Cross(que[last].v, que[last - 1].v)) < eps) {
			last--;
			if(OnLeft(que[last], L[i].p)) que[last] = L[i];
		}
		if(first < last) p[last - 1] = LineInter(que[last], que[last - 1]);
	}
	while(first < last && !OnLeft(que[first], p[last - 1])) last--;
	if(last - first <= 1) return ans;
	p[last] = LineInter(que[first], que[last]);
	for(int i = first; i <= last; i++) {
		ans.push_back(p[i]);
	}
	return ans;
}

int main() {
	//("E:1.in", "r", stdin);
	int n;
	while(~scanf("%d", &n)) {
		vector<Point> p;
		int x, y;
		for(int i = 0; i < n; i++) {
			scanf("%d%d", &x, &y);
			p.push_back(Point(x, y));
		}
		reverse(p.begin(), p.end());
		int left = 0, right = n;
		while(left <= right) {
			int mid = left + right >> 1;
			vector<Line> L;
			for(int i = 0; i < n; i++) {
				L.push_back(Line(p[i], p[(i + mid + 1) % n] - p[i]));
			}
			vector<Point> pp = HalfplaneIntersection(L);
			if(pp.empty()) right = mid - 1;
			else left = mid + 1;
			// printf("%d   %d   %d \n", left, mid, right);
		}
                //这要输出了答案是left 跟right没有关系
		printf("%d\n", left);
		// printf("%d\n", right);
	}
	return 0;
}
posted @ 2017-05-04 21:12  s1124yy  阅读(332)  评论(0)    收藏  举报
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