天下技术殊途同归
叶问:你错了,不是南北拳的问题,是你的问题

普通的数组数据交换,

    let mut val = [1,2,3];

    let t = val[0];
    val[0] = val[1];
    val[1] = t;

it works...下面的也work:

    let mut val = ["1","2","3"];

    let t = val[0];
    val[0] = val[1];
    val[1] = t;

但,

   let mut val = ["1".to_string(),"2".to_string(),"3".to_string()];
   
    let t = val[0];
    val[0] = val[1];
    val[1] = t;

编译出错:

<anon>:32:13: 32:19 error: cannot move out of type `[collections::string::String; 3]`, a non-copy fixed-size array
<anon>:32     let t = val[0];
                      ^~~~~~
<anon>:32:9: 32:10 note: attempting to move value to here
<anon>:32     let t = val[0];
                  ^
<anon>:32:9: 32:10 help: to prevent the move, use `ref t` or `ref mut t` to capture value by reference
<anon>:33:14: 33:20 error: cannot move out of type `[collections::string::String; 3]`, a non-copy fixed-size array
<anon>:33     val[0] = val[1];
                       ^~~~~~
error: aborting due to 2 previous errors

  正确的交换方式是,


    val.swap(0,1);
   

posted on 2015-06-11 23:38  rxlinq  阅读(187)  评论(0)    收藏  举报