按分类查找缺陷并输出到EXCEL

import pymysql,xlwt
def export_excel(table_name):
host,user,passwd,db='192.168.1.10','root','zentao_123','zentao'
coon=pymysql.connect(host=host,user=user,passwd=passwd,db=db,port=3306,charset='utf8')
cur=coon.cursor() #建立游标
sql='''SELECT
type,
count( * ) AS 激活数量,
sum( IF ( severity = 1, 1, 0 ) ) AS 1级数量,
sum( IF ( severity = 2, 1, 0 ) ) AS 2级数量,
sum( IF ( severity = 3, 1, 0 ) ) AS 3级数量,
sum( IF ( severity = 4, 1, 0 ) ) AS 4级数量
FROM
zt_bug
WHERE
product = '189'
AND STATUS = 'active'
GROUP BY
type'''
cur.execute(sql)#执行sql
fileds=[filed[0] for filed in cur.description]#所有字段
all_data=cur.fetchall()#所有值
print(all_data)
book=xlwt.Workbook()
sheet=book.add_sheet('sheet1')
for col,filed in enumerate(fileds):
sheet.write(0,col,filed)
row = 1
for data in all_data:
for index, datacol in enumerate(data): # 控制列
sheet.write(row, index, datacol)
row = row+ 1
book.save('%s.xls' %table_name)
export_excel('zentao.zt_bug') # 导出excel

https://www.cnblogs.com/jiajunplyh/p/12150433.html
posted @ 2021-07-01 15:13  小蕊-zr  阅读(54)  评论(0编辑  收藏  举报