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联赛模拟测试15

A.游戏

(不)排序+乱搞/暴力/二分图/冰茶几(正解) 均可AC
考场上手动模拟了20以内的数据都hack掉了
没想到交上过了
,,,
就挺意外的

B.嘟嘟噜

搞一搞,对于中间不用取模的地方,不再使用加法,而是直接乘过去,调整下标

Code
#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>
#include <queue>
#include <cmath>
using namespace std;

inline int read(){
	int x = 0, w = 1;
	char ch = getchar();
	for(; ch > '9' || ch < '0'; ch = getchar()) if(ch == '-') w = -1;
	for(; ch >= '0' && ch <= '9'; ch = getchar()) x = x * 10 + ch - '0';
	return x * w;
}

inline void write(register int x){
	if(x < 0) x = ~x + 1, putchar('-');
	if(x > 9) write(x / 10);
	putchar(x % 10 + '0');
}

signed main(){
    freopen("mayuri.in","r",stdin);
    freopen("mayuri.out","w",stdout);
    register int T = read();
    while(T--){
        int n = read(), m = read(), x = 0, i = m;
        for(register int j = 2; j <= min(n, m); j++)
            x=(x+m)%j;
        if(n <= m) printf("%d\n", x + 1);
        else{
            x += 1;
            while("GARY CSL"){
                int nxt = i + (int)ceil(1.0 * (i - x) / (m - 1));
                if(nxt > n)break;
                x = (x + (nxt - i) * m);
                if(x == nxt){
                    if(++nxt > n) break;
                    x = (x + m) % nxt;
                }else x %= nxt;
                i = nxt;
            }
            x += (n - i) * m;
            printf("%d\n", x);
        }
    }
    return 0;
}

C.天才绅士少女助手克里斯蒂娜

化简柿子
线段树维护\(x^2,y^2,xy\)即可

Code
#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>
#define ls (u << 1)
#define rs (ls | 1)
using namespace std;

inline int read(){
	int x = 0, w = 1;
	char ch = getchar();
	for(; ch > '9' || ch < '0'; ch = getchar()) if(ch == '-') w = -1;
	for(; ch >= '0' && ch <= '9'; ch = getchar()) x = x * 10 + ch - '0';
	return x * w;
}

inline void write(register int x){
	if(x < 0) x = ~x + 1, putchar('-');
	if(x > 9) write(x / 10);
	putchar(x % 10 + '0');
}

const int ss = 1000010;
const int mod = 20170927;

struct node{
	long long xx, yy, xy;
}tr[ss << 2];

struct ANS{
	long long a, b, c;
	inline void init(){a = 0, b = 0, c = 0;}
	inline ANS operator + (const ANS &A) const {
		ANS B;
		B.a = (long long)(A.a + a) % mod;
		B.b = (long long)(A.b + b) % mod;
		B.c = (long long)(A.c + c) % mod;
		return B;
	}
	inline void print(){
		write((a * b % mod -  c * c % mod + mod) % mod);
		puts("");
	}
};

int a[ss], b[ss];
inline void push_up(register int u){
	tr[u].xx = (tr[ls].xx + tr[rs].xx) % mod;
	tr[u].yy = (tr[ls].yy + tr[rs].yy) % mod;
	tr[u].xy = (tr[ls].xy + tr[rs].xy) % mod;
}

inline void build(register int u, register int l, register int r){
	if(l == r){
		tr[u].xx = a[l] * a[l];
		tr[u].yy = b[l] * b[l];
		tr[u].xy = a[l] * b[l];
		return;
	}
	register int mid = l + r >> 1;
	build(ls, l, mid);
	build(rs, mid + 1, r);
	push_up(u);
}

inline void change(register int u, register int l, register int r, register int pos, register int modify_x, register int modify_y){
	if(l == r){
		tr[u].xx = 1ll * modify_x * modify_x % mod;
		tr[u].yy = 1ll * modify_y * modify_y % mod;
		tr[u].xy = 1ll * modify_x * modify_y % mod;
		return;
	}
	register int mid = l + r >> 1;
	if(pos <= mid) change(ls, l, mid, pos, modify_x, modify_y);
	else change(rs, mid + 1, r, pos, modify_x, modify_y);
	push_up(u);
}

inline ANS query(register int u, register int l, register int r, register int s, register int t){
	if(s <= l && t >= r){
		register ANS ans;
		ans.a = tr[u].xx;
		ans.b = tr[u].yy;
		ans.c = tr[u].xy;
		return ans;
	}
	register ANS ans;
	ans.init();
	register int mid = l + r >> 1;
	if(s <= mid) ans = ans + query(ls, l, mid, s, t);
	if(t > mid) ans = ans + query(rs, mid + 1, r, s, t);
	return ans;
}

signed main(){
	freopen("kurisu.in", "r", stdin);
	freopen("kurisu.out", "w", stdout);
	register int n = read(), m = read();
	for(register int i = 1; i <= n; i++) a[i] = read(), b[i] = read();
	build(1, 1, n);
	while(m--){
		register int op = read();
		if(op == 1){
			register int k = read(), x = read(), y = read();
			change(1, 1, n, k, x, y);
		}
		else{
			register int l = read(), r = read();
			register ANS ans = query(1, 1, n, l, r);
			ans.print();
		}
	}
	return 0;
}

D.凤凰院凶真

维护最长公共上升子序列
学习老姚课件

Code
#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>
#define ls (u << 1)
#define rs (ls | 1)
using namespace std;

inline int read(){
	int x = 0, w = 1;
	char ch = getchar();
	for(; ch > '9' || ch < '0'; ch = getchar()) if(ch == '-') w = -1;
	for(; ch >= '0' && ch <= '9'; ch = getchar()) x = x * 10 + ch - '0';
	return x * w;
}

inline void write(register int x){
	if(x < 0) x = ~x + 1, putchar('-');
	if(x > 9) write(x / 10);
	putchar(x % 10 + '0');
}

const int ss = 5200;

int n, m, ans, posx, posy;
int a[ss], b[ss];
int f[ss][ss], pre[ss][ss];

inline void Print (register int i, register int j) {
	if (i == 0) return;
	Print (i - 1, pre[i][j]);
	if (f[i][j] != f[i - 1][pre[i][j]]) {
		write (b[j]), putchar (' ');
	}
}

int main () {
	freopen ("phoenix.in", "r", stdin);
	freopen ("phoenix.out", "w", stdout);
	n = read();
	for (register int i = 1; i <= n; i ++) a[i] = read();
	m = read();
	for (register int i = 1; i <= m; i ++) b[i] = read();
	for (register int i = 1; i <= m; i ++) {
		if (a[1] == b[i]) f[1][i] = 1;
	}
	for (register int i = 1; i <= n; i ++) {
		if (b[1] == a[i]) f[i][1] = 1;
	}
	for (register int i = 1; i <= n; i ++) {
		register int maxx = 0, k = 0;
		for (register int j = 1; j <= m; j ++) {
			f[i][j] = f[i - 1][j], pre[i][j] = j;
			if (b[j] < a[i] && maxx < f[i - 1][j]) maxx = f[i - 1][j], k = j;
			if (a[i] == b[j]) f[i][j] = maxx + 1, pre[i][j] = k;
			if (ans < f[i][j]) ans = f[i][j], posx = i, posy = j;
		}
	}
	write (ans), putchar ('\n');
	Print (posx, posy), putchar ('\n');
	return 0;
}
posted @ 2020-10-13 16:18  Gary_818  阅读(21)  评论(0编辑  收藏