右击DataGrid产生菜单
This example programmatically creates a Windows Forms context menu and associates it with a control.
Example
private void Form1_Load(object sender, System.EventArgs e)
{
System.Windows.Forms.ContextMenu contextMenu1;
contextMenu1 = new System.Windows.Forms.ContextMenu();
System.Windows.Forms.MenuItem menuItem1;
menuItem1 = new System.Windows.Forms.MenuItem();
System.Windows.Forms.MenuItem menuItem2;
menuItem2 = new System.Windows.Forms.MenuItem();
System.Windows.Forms.MenuItem menuItem3;
menuItem3 = new System.Windows.Forms.MenuItem();
contextMenu1.MenuItems.AddRange(new System.Windows.Forms.MenuItem[] {menuItem1, menuItem2, menuItem3});
menuItem1.Index = 0;
menuItem1.Text = "MenuItem1";
menuItem2.Index = 1;
menuItem2.Text = "MenuItem2";
menuItem3.Index = 2;
menuItem3.Text = "MenuItem3";
textBox1.ContextMenu = contextMenu1;
}
Compiling the Code
This example requires:
- A Windows Form named Form1 and a TextBox control named textBox1. Set Form1's Load event handler to Form1_Load.
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