Java -- Map
HashMap
- 继承关系

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遍历
// initialize a HashMap HashMap<String, Integer> map = new HashMap<>(); // Iterate the map using // for-each loop for (Map.Entry<String, Integer> e : map.entrySet()) System.out.println("Key: " + e.getKey() + " Value: " + e.getValue()); -
如何随机获取一个键值对?
Map<String,Integer> mapTest = new HashMap<>(); mapTest.put("one",1); mapTest.put("two",2); mapTest.put("three",3); Random r = new Random(); int randNum = r.nextInt(3); Set keys = mapTest.keySet(); System.out.println(keys.toArray()[randNum]); -
有时需要使用有序的HashMap 即 LinkedHashMap
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使用LinkedHashMap更改一个键的值不会更改顺序,键的顺序在初始映射时已被固定。
"key1" -> "value1" "key2" -> "value2" "key3" -> "value3" "key4" -> "value4" "key5" -> "value5" change to "key1" -> "value1" "key2" -> "value8" "key3" -> "value3" "key4" -> "value6" "key5" -> "value5" //方法 map.put("key2","value8"); map.put("key4","value6");
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注意需要存储相同键不同值时不要使用map

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