C#打开文件夹

            FolderBrowserDialog dialog = new FolderBrowserDialog();
            dialog.ShowDialog();

            pathName = dialog.SelectedPath;
            this.xmlPathValue1.Text = pathName;
            glbllt = readXMLPath(pathName);

  

posted @ 2022-04-15 16:38  Joooannes  阅读(1706)  评论(0)    收藏  举报