while(Thread.activeCount() > 1)

今天看到深入理解JVM第367页多线程volatile部分照着书本敲着代码发现了一个问题 Thread.activeCount()会一直大于2

public class VolatileTest {
public static volatile int race = 0;

public static void increase() {
race++;
}

private static final int THREADS_COUNT = 20;

public static void main(String[] args) {
Thread[] threads = new Thread[THREADS_COUNT];
for (int i = 0; i < THREADS_COUNT; i++) {
threads[i] = new Thread(new Runnable() {
@Override
public void run() {
for (int i = 0; i < 10000; i++) {
increase();
}
}
});
threads[i].start();
}
while (Thread.activeCount() > 1) {
Thread.yield();
}
System.out.println(race);
}
}

陷入了死循环.......why?

Thread.yield();//应该主线程先让出cpu使用权

问题在这Thread.activeCount() 还有个守护线程!!!所以就会一直陷入无限循环。

加了一句Thread.currentThread().getThreadGroup().list();

while (Thread.activeCount() > 1) {
Thread.currentThread().getThreadGroup().list();
Thread.yield();
}

posted @ 2018-05-29 17:01  罗贱人  阅读(845)  评论(1)    收藏  举报