POJ 1222 EXTENDED LIGHTS OUT 高斯消元

最基本的高斯消元异或方程解决开关灯问题

#include <cstdio>
#include <cstring>
#include <algorithm>
#include <queue>
#include <stack>
#include <map>
#include <set>
#include <climits>
#include <iostream>
#include <string>

using namespace std;
 
#define MP make_pair
#define PB push_back
typedef long long LL;
typedef unsigned long long ULL;
typedef vector<int> VI;
typedef pair<int, int> PII;
typedef pair<double, double> PDD;
const int INF = INT_MAX / 3;
const double eps = 1e-8;
const LL LINF = 1e17;
const double DINF = 1e60;
const int maxn = 40;
const int dx[] = {0, 0, 1, -1};
const int dy[] = {1, -1, 0, 0};

int a0[maxn][maxn], a[maxn][maxn], ans[maxn][maxn];

void init() {
    for(int i = 0; i < 5; i++) {
        for(int j = 0; j < 6; j++) {
            int u = i * 6 + j;
            a0[u][u] = 1;
            for(int k = 0; k < 4; k++) {
                int nx = i + dx[k], ny = j + dy[k], nu = nx * 6 + ny;
                if(nx >= 0 && nx < 5 && ny >= 0 && ny < 6) {
                    a0[nu][u] = a0[u][nu] = 1;
                }
            }
        }
    }
}

void gauss() {
    for(int i = 0; i < 30; i++) {
        int k = i;
        while(a[k][i] == 0 && k < 30) k++;
        for(int j = 0; j <= 30; j++) swap(a[i][j], a[k][j]);
        for(int j = 0; j < 30; j++) {
            if(i != j && a[j][i] != 0) {
                for(int k = 0; k <= 30; k++) {
                    a[j][k] = a[i][k] ^ a[j][k];
                }
            }
        }
    }
}

int main() {
    init();
    int T, kase = 1; scanf("%d", &T);
    while(T--) {
        memcpy(a, a0, sizeof(a0));
        for(int i = 0; i < 30; i++) scanf("%d", &a[i][30]);
        gauss();
        for(int i = 0; i < 30; i++) {
            int x = i / 6, y = i % 6;
            if(a[i][30]) ans[x][y] = 1;
            else ans[x][y] = 0;
        }
        printf("PUZZLE #%d\n", kase++);
        for(int i = 0; i < 5; i++) {
            for(int j = 0; j < 6; j++) {
                printf("%d ", ans[i][j]);
            }
            puts("");
        }
    }
    return 0;
}

  

posted @ 2014-11-01 09:53  acm_roll  阅读(145)  评论(0编辑  收藏  举报