摘要:出现这个错误基本由于Lambda中没有显示地说明返回值类型,而是由编译器自己推断返回值。下面是从C++11官方文档中抄过来的 If a lambda-expression does not include a trailing-return-type, it is as if the trailing-return-type denotes the following type: ...
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posted @ 2013-04-16 13:35
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