第三次

1.输入一个年份,判断是不是闰年(能被4整除但不能被100整除,或者能被400整除)

package tk;
import java.util.Scanner;
public class work {
    public static void main(String[] args) {
        Scanner input=new Scanner(System.in);
        System.out.println("输入年份:");
        int year=input.nextInt();
        if(year%4==0&&year%100!=0||year%400==0){
            System.out.println(year+"年是闰年");
        }else{
            System.out.println(year+"年不是闰年");
        }
    }
}

 

 2.输入一个4位会员卡号,如果百位数字是3的倍数,就输出是幸运会员,否则就输出不是.

package tk;
import java.util.Scanner;
public class work {
    public static void main(String[] args) {
        Scanner input=new Scanner(System.in);
        System.out.println("请输入会员号：");
        int hy=input.nextInt();
        if((hy%1000/100)%3==0){
            System.out.println("是幸运会员");
        }else if(hy<1000){
            System.out.println("不是会员号");
        }else{
            System.out.println("不是幸运会员");
        }
    }
}

 

 

 

 

3.已知函数,输入x的值,输出对应的y的值.
        x + 3 ( x > 0 )
y =  0 ( x = 0 )
        x*2 –1 ( x < 0 )

package tk;
import java.util.Scanner;
public class work {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        System.out.println("输入x的值:");
        int x = input.nextInt();   
        if (x>0) {
           System.out.println("y="+(x+3));
       }else if (x<0) {
           System.out.println("y="+(x*2-1));
       }else {
           System.out.println("y=0");
       }
    }
}

 

 

4.输入三个数,判断能否构成三角形(任意两边之和大于第三边)

package tk;
import java.util.Scanner;
public class work {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        System.out.println("输入三个数:");
        int a = input.nextInt();
        int b = input.nextInt();
        int c = input.nextInt();
        if (a+b>c&&a+c>b&&b+c>b){
            System.out.println("可以构成三角形");
        }else{
            System.out.println("不行");
        }
    }
}