计算三角形的周长以及面积

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
 
namespace S
{
    class Program
    {
        static void Main()
        {
            Program p = new Program();
            p.a();
             
        }
        public void a()
        {
            Double[] a=new Double[6];
             
            for (int i = 0; i < 6; i++)
            {
                if(i % 2 == 0){
                    Console.WriteLine("请输入第{0}个点坐标 :",( i + 2 ) / 2);
                }
                    a[i] = double.Parse(Console.ReadLine());
            }
            double b = Math.Sqrt((a[0] - a[2]) * (a[0] - a[2]) + (a[1] - a[3]) * (a[1] - a[3]));
            double c = Math.Sqrt((a[2] - a[4]) * (a[2] - a[4]) + (a[3] - a[5]) * (a[3] - a[5]));
            double e = Math.Sqrt((a[4] - a[0]) * (a[4] - a[0]) + (a[5] - a[1]) * (a[5] - a[1]));
            Console.WriteLine("三个边长长度为{0},{1},{2}:", b, c, e);
            double f = (e + b + c) / 2;
            double h = e + b + c;
            Console.WriteLine("三角形的周长是:{0}",h);
            double S = Math.Sqrt(f * (f - b) * (f  - c) * (f - e));
            Console.WriteLine("该三角形的面积为:{0}",S);
        }
    }
}

转载至 http://www.oschina.net/code/snippet_1775790_46681

posted @ 2015-07-06 11:19  如.若  阅读(749)  评论(0编辑  收藏  举报