实验4

task 1

#include <stdio.h>
#include<stdlib.h>
#define N 4
int main() {
    int a[N]={1,9,8,4};
    char b[N] = { '1','9','8','4' };
    int i;

    printf("sizeof(int)=%d\n", sizeof(int));
    printf("sizeof(char)=%d\n", sizeof(char));
    printf("\n");

    for (i = 0;i < N;i++) {
        printf("%p: %d\n", &a[i], a[i]);
    }
    printf("\n");
    printf("a=%p\n", a);
    printf("b=%p\n", b);

    system("pause");
    return 0;
}

 

 

 

#include <stdio.h>
#include<stdlib.h>
#define N 2
#define M 4

int main() {
    int a[N][M] = { {1, 9, 8, 4}, {2, 0, 2, 2} };
    char b[N][M] = { {'1', '9', '8', '4'}, {'2', '0', '2', '2'} };
    int i, j;
    for (i = 0; i < N; ++i){
        for (j = 0; j < M; ++j) {
            printf("%p: %d\n", &a[i][j], a[i][j]);
        }
    }
    printf("\n");

    for (i = 0; i < N; ++i) {
        for (j = 0; j < M; ++j) {
            printf("%p: %c\n", &b[i][j], b[i][j]);
        }
    }
    system("pause");
    return 0;
}

 

 task2

 

#include <stdio.h>
#define N 13

int days_of_year(int year, int month, int day);

int main() {
    int year, month, day;
    int days;

    while (scanf_s("%d%d%d", &year, &month, &day) != EOF) {
        days = days_of_year(year, month, day);
        printf("%4d-%02d-%02d是这一年的第%d天.\n\n", year, month, day, days);
    }

    return 0;
}
int days_of_year(int year, int month, int day) {
    int a[13] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 };
    int b=1;
    int days=0;
    
        for (b = 1; b < month; b++)
            days += a[b];
        if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0)
        {
            if (month > 2)
                days = days + day + 1;
        }
        else
            days = days + day;
        return days;

}

 

 task3

#include <stdio.h>
#include<stdlib.h>
#define N 5

void input(int x[], int n);
void output(int x[], int n);
double average(int x[], int n);
void bubble_sort(int x[], int n);

int main() {
    int scores[N];
    double ave;

    printf("录入%d个分数:\n", N);
    input(scores, N);

    printf("\n输出课程分数: \n");
    output(scores, N);

    printf("\n课程分数处理: 计算均分、排序...\n");
    ave = average(scores, N);
    bubble_sort(scores, N);

    printf("\n输出课程均分: %.2f\n", ave);
    printf("\n输出课程分数(高->低):\n");
    output(scores, N);

    system("pause");
    return 0;
}


void input(int x[], int n) {
    int i;

    for (i = 0; i < n; ++i)
        scanf_s("%d", &x[i]);
}

void output(int x[], int n) {
    int i;

    for (i = 0; i < n; ++i)
        printf("%d ", x[i]);
    printf("\n");
}

double average(int x[], int n) {
    int a = 0, b = 0;
    for (b = 0; b <= n - 1; b++)
        a += x[b];
    return a / n;
}

void bubble_sort(int x[], int n) {

    int j, i, t;
    for (j = 0; j < n - 1; j++)
        for (i = 0; i < n - j - 1; i++)
            if (x[i] <x[i + 1])
            {
                t = x[i];
                x[i] = x[i + 1];
                x[i+1]=t;
            }
    for (i = 0; i < n; i++)
        printf("%d", x[i]);
}

 

 task 4

#include <stdio.h>
#define N 100
void dec2n(int x, int n); // 函数声明
int main() {
int x;
printf("输入一个十进制整数: ");
while(scanf("%d", &x) != EOF) {
dec2n(x, 2); // 函数调用: 把x转换成二进制输出
dec2n(x, 8); // 函数调用: 把x转换成八进制输出
dec2n(x, 16); // 函数调用: 把x转换成十六进制输出
printf("\n输入一个十进制整数: ");
}
return 0;
}
void dec2n(int x, int n) {
    char a[16] = { '0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};
    char b[100];
    int i, count = 0;
    while (x != 0) {
        b[++count] = a[x % n];
        x = x / n;
    }
    for (i = count;i > 0;i--) {
        printf("%c", b[i]);
    }
    printf("\n");

}

 

 task5

#include <stdio.h>
#define N 100

// 函数声明
void func(int x[][N], int n);   // 注意：两维数组作为形参的语法
void output(int x[][N], int n); // 注意：两维数组作为形参的语法

int main() {
    int x[N][N];
    int i, j, n;

    printf("Enter n: ");
    while(scanf("%d", &n) != EOF) {
        func(x, n);     // 注意：两维数组作为实参的语法
        output(x, n);   // 注意：两维数组作为实参的语法
        
        printf("\nEnter n: ");
    }

    return 0;
}

// 函数定义
// 功能：输出两维数组x中的数据，数据项n行、n列
void output(int x[][N], int n) {
    int i, j;

    for(i = 0; i < n; ++i) {
        for(j = 0; j < n; ++j) 
            printf("%5d", x[i][j]);
        
        printf("\n");
    }
}

void func(int x[][N], int n){
    int i,j;
    for(i=0;i<n;++i){
        for(j=0;j<n;++j){
            if(i<j)
            x[i][j]=i+1;
            else
            x[i][j]=j+1;
        }
    }
}

 

 task 6

#include <stdio.h>
#include <string.h>
#include<stdlib.h>
#define N 80

int main() {
char views1[N] = "hey, C, I have not love u yet.";
char views2[N] = "hey, C, how can I love u?";
char t[N];

printf("交换前: \n");
printf("views1: %s\n", views1);
printf("views2: %s\n", views2);

strcpy(t, views1);
strcpy(views1, views2);
strcpy(views2, t);

printf("交换后: \n");
printf("views1: %s\n", views1);
printf("views2: %s\n", views2);

system("pause");
return 0;
}

 

 

#include <stdio.h>
#include <string.h>
#include<stdlib.h>
#define N 80

int main() {
    char views[2][N] = { "hey, C, I have not love u yet.",
                         "hey, C, how can I love u?" };

    char t[N];

    printf("交换前: \n");
    printf("views1: %s\n", views[0]);
    printf("views2: %s\n", views[1]);

    // 交换
    strcpy(t, views[0]);
    strcpy(views[0], views[1]);
    strcpy(views[1], t);

    printf("交换后: \n");
    printf("views1: %s\n", views[0]);
    printf("views2: %s\n", views[1]);

    system("pause");
    return 0;
}

 

 task7

#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>
#include <string.h>
#include<stdlib.h>

#define N 5
#define M 20

void bubble_sort(char str[][M], int n); // 函数声明

int main() {
    char name[][M] = { "Bob", "Bill", "Joseph", "Taylor", "George" };
    int i;

    printf("输出初始名单:\n");
    for (i = 0; i < N; i++)
        printf("%s\n", name[i]);

    printf("\n排序中...\n");
    bubble_sort(name, N);  // 函数调用 

    printf("\n按字典序输出名单:\n");
    for (i = 0; i < N; i++)
        printf("%s\n", name[i]);
    
    system("pause");
    return 0;
}
void bubble_sort(char str[][M], int n) {
    int i, j, k;
    char tem[100][M];
    for (k = 0;k < n;k++) {
        for (i = 0;i < n - 1;i++) {
            if (strcmp(str[i], str[i + 1]) > 0) {
                for (j = 0;j < n;j++) {
                    tem[i][j] = str[i][j];
                    str[i][j] = str[i + 1][j];
                    str[i + 1][j] = tem[i][j];
                }
            }
        }
    }
}