快速寻找满足条件的2个数

//快速寻找满足条件的2个数
    
    int icy[]={1,2,3,4,5,6,7,8,9,10};
    int i=0;
    int j=9;
    int key=11;

    while(i<j)
    {
        if(icy[i]+icy[j]==key)
        {
            std::cout<<icy[i]<<" "<<icy[j]<<" ";
            i++;
            j--;
            std::cout<<endl;
        }
        else if(icy[i]+icy[j]<key)
        {
            i++;
        }
        else if(icy[i]+icy[j]>key)
        {
            j--;
        }
    }

 

    //计算差为 key
    i=0;
    j=1;
    while(j<=9&&i<j)
    {
       if(icy[j]-icy[i]==key)
       {
             std::cout<<icy[i]<<" "<<icy[j]<<" ";
            i++;
            j++;
            std::cout<<endl;
       }
       else if(icy[j]-icy[i]>key)
       {
           i++;
       }
       else
       {
           j++;
       }
    }