hdu 1061 暴力
Rightmost Digit
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 29108 Accepted Submission(s): 11115
Problem Description
Given a positive integer N, you should output the most right digit of N^N.
Input
The
input contains several test cases. The first line of the input is a
single integer T which is the number of test cases. T test cases follow.
Each test case contains a single positive integer N(1<=N<=1,000,000,000).
Each test case contains a single positive integer N(1<=N<=1,000,000,000).
Output
For each test case, you should output the rightmost digit of N^N.
Sample Input
2
3
4
Sample Output
7
6
Hint
In the first case, 3 * 3 * 3 = 27, so the rightmost digit is 7.
In the second case, 4 * 4 * 4 * 4 = 256, so the rightmost digit is 6.
Author
Ignatius.L
低位相乘与高位无关
import java.util.Scanner;
public class Main {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner s = new Scanner(System.in);
int t = s.nextInt();
for(int i=0; i<t; i++){
int n=s.nextInt();
int[][] a ={
{0},{1},{6,2,4,8},
{1,3,9,7},
{6,4},
{5},
{6},
{1,7,9,3},
{6,8,4,2},
{1,9}
};
int[] l = {1,1,4,4,2,1,1,4,4,2};
int d = n%10;
System.out.println(a[d][n%l[d]]);
}
}
}

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