2020HDU多校第八场By Rynar 6867-6876

1002.Absolute Math

思路：借鉴于https://www.cnblogs.com/DeaphetS/p/13525554.html

1003.Slime and Stones

思路；betty定理，1/x+1/(x+k+1)=1的大解，(a-b)/(k+1)*x==a时，为奇异局势，输出0，否则输出1

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define int ll
int n,m,k;
signed main(){
    int T;
    scanf("%lld",&T);
    while (T--){
        scanf("%lld%lld%lld",&n,&m,&k);
        if (n>m)swap(n,m);
        double x=(1-k+sqrt(k*k+2*k+5))/2.0;
        if ((m-n)%(k+1)){
            puts("1");continue;
        }
        int r=(m-n)/(k+1)*x;
        if (r==n)puts("0");
        else puts("1");
    }
    return 0;
}

1007.Game