shell输出台阶状图形

shell输出台阶状图形

程序如下:

#!/bin/bash

rows=4

for (( i=1; i<=rows; i++ ))
do
  for (( j=1; j<=i; j++ ))
  do
    echo -n "| "
  done
  echo -n "_"
  echo
done

# |_
# ||_

posted @ 2023-05-09 22:17  七色彩虹k  阅读(40)  评论(0)    收藏  举报