sql 通过一个数值获取有哪些小数值组成

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
ALTER PROCEDURE GetAllBinByBigInt
@bigint bigint
AS
BEGIN
SET NOCOUNT ON;
DECLARE @Bin_value varchar(50)
DECLARE @Sql nvarchar(max)
DECLARE @str_b varchar(50)
DECLARE @str_e varchar(50)
DECLARE @condition varchar(5)
DECLARE @likevalue varchar(30)
DECLARE @index int
DECLARE @tvalue varchar(30)
DECLARE @index2 int

SET @condition=' '
SET @Sql='SELECT * FROM TEST WHERE 1=1 AND ( '
SET @Bin_value=dbo.dec2bin(@bigint,26)

SET @likevalue=''
SET @index=0
SET @index2=0
WHILE(@index<26)
BEGIN
SET @tvalue=substring(@Bin_value,@index+1,1)
IF(@tvalue='1')
BEGIN
SET @likevalue=''
SET @index2=0
WHILE(@index2<26)
BEGIN
IF(@index=@index2)
BEGIN
SET @likevalue=@likevalue+'1'
END
ELSE
BEGIN
SET @likevalue=@likevalue+'_'
END
SET @index2=@index2+1
END

SET @sql=@sql+@condition+' dbo.dec2bin(tid,26) like '''+@likevalue+''' '
IF(len(@likevalue)>0)
BEGIN
SET @condition=' OR '
END
END
SET @index=@index+1
END

SET @sql=@sql+' ) '
print @sql
EXEC SP_EXECUTESQL @sql
END

GO

================================================

set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
GO
ALTER FUNCTION [dbo].[Dec2Bin](@Dec INT, @StrLen TINYINT)
RETURNS VARCHAR(31) -- INT型,4字节,正数转为二进制字符串最多31位
AS
BEGIN
DECLARE @BinStr AS VARCHAR(31) -- 二进制表示的字符串
DECLARE @Div2 AS INT -- 商
DECLARE @Mod2 AS INT -- 模/余数
IF @Dec < 0
RETURN 'NULL' -- 不支持负数的转换
SET @Div2 = @Dec / 2
SET @Mod2 = @Dec % 2
SET @BinStr = ''
WHILE @Div2 <> 0
BEGIN
SET @BinStr = CAST(@Mod2 AS CHAR(1)) + @BinStr
SET @Dec = @Dec / 2
SET @Div2 = @Dec / 2
SET @Mod2 = @Dec % 2
END

SET @BinStr = CAST(@Mod2 AS CHAR(1)) + @BinStr -- 至此,已完成十进制到二进制的转换
IF @StrLen > LEN(@BinStr) -- 如果用户指定的长度大于实际长度，则需要左边补0
BEGIN
IF @StrLen > 31 -- 返回的长度，最长为32
SET @StrLen = 31

DECLARE @ZeroStr VARCHAR(31) -- 需要补充的"0000..."
DECLARE @OffsetLen TINYINT -- 需要补充几个"0"
SET @ZeroStr = ''
SET @OffsetLen = @StrLen - LEN(@BinStr)

WHILE @OffsetLen > 0
BEGIN
SET @ZeroStr = @ZeroStr + '0'
SET @OffsetLen = @OffsetLen - 1
END

SET @BinStr = @ZeroStr + @BinStr
END
RETURN @BinStr
END