第四次作业

1. 教材P52 例4-8 分数转成等级 switch

#include<stdio.h>

main()

{

         int mark;

         printf("请输入学生的分数(0-100):\n");

         scanf("%d",&mark);

         switch(mark/10)

         {

         case 10:

         case 9:printf("A\n");break;

         case 8:printf("B\n");break;

         case 7:printf("C\n");break;

         case 6:printf("D\n");break;

         default:printf("NO PASS!\n");

         }

}

 

 

 

 

2. 编写程序，根据x值，求出相应y的值

#include<stdio.h>

main()

{

         float x,y;

         printf("请输入x的值:\n");

         scanf("%f",&x);

         if(x>0)

                  y=x*x+1;

         else if(x==0)

                  y=0;

         else

         y=-x*x-1;

         printf("x=%f\ny=%f\n",x,y);

 

}

 

 

 

 

3. 使用多分支选择结构，实现两个数加、减、乘、除的简单计算器

#include<stdio.h>

main()

{

         float n1,n2;

         char sign;

         printf("请输入计算的表达式:\n");

         scanf("%f%c%f",&n1,&sign,&n2);

         switch(sign)

         {

                  case'+':printf("n1+n2=%f\n",n1+n2);break;

                  case'-':printf("n1-n2=%f\n",n1-n2);break;

                  case'*':printf("n1*n2=%f\n",n1*n2);break;

                  case'/':printf("n1/n2=%f\n",n1/n2);break;

 

         }

 

}

 

 

 

4输入年份判断是不是闰年（闰年条件：能被四4整除但不能被100整除或者能被400整除）

#include<stdio.h>

main()

{

         int year,a;

         printf("请输入年份:\n");

         scanf("%d",&year);

         if(year%400==0)

         {

                  a=1;

         }

         else

         {

                  if(year%4==0&&year%100==0)

                  a=1;

                  else

                  a=0;

         }

         if(a==1)

         {

                  printf("%d是闰年\n",year);

         }

         else

         {

                  printf("%d不是闰年\n",year);

         }

}

 

 

 

5．编写程序，使用条件运算符找出三个数中最小的数字，并输出

#include<stdio.h>

main()

{

         float a,b,c,min;

         scanf("%f%f%f",&a,&b,&c);

         min=a<b?a:b;

         min=min<c?min:c;

         printf("Min:%f\n",min);

 

}

 

 

 

6.编写程序，判断整数m是否能被4和6同时整除

#include<stdio.h>

main()

{

         int m;

         scanf("%d",&m);

         if(m%4==0&&m%6==0)

                  printf("Yes\n");

         else

                  printf("No\n");

 

}